The correct option is c. how the birds dealt with gradually steeper inclines.
After Ken Dial had his "‘aha’ moment" (line 41), he observed how the birds dealt with gradually steeper inclines.
<h3>Who was
Ken Dial?</h3>
In 1988, Dr. Dial was appointed as a biology professor at the of Montana. Dial was the creator and deputy director of the University of Montana Flight Laboratory, as well as the director of the University of Montana Field Research Facility at Fort Missoula.
Some key features regarding Ken Dial are-
- He taught graduate courses in East African evolutionary biology for three decades.
- Ken, a pilot with over 35 years of experience, is certified to fly numerous types of jet aircraft but loves backcountry flying onto remote airfields as in Montana-Idaho wilderness.
- Ken created and presented 26 episodes of "All Bird TV" on the Animal Planet channel of the Discovery Channel.
- Dial is still a frequent keynote speaker at scientific & aeronautical conferences across the world.
- He just left his full-time position as a professor at the University of Montana to devote more time to wildlife & land conservation initiatives in Tanzania, Kenya, southern California, and western Montana.
To know more about land conservation, here
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2x^2 + 4x + 1 = 0
2x^2 + 4x + 1 - 1 = 0 - 1
2x^2 + 4x = -1
X(2x + 4) = -1
X = -1.
2x + 4 = -1
2x + 4 - 4 = -1 - 4
2x = -5
2x/2 = -5/2
X = -5/2.
I believe these are the solutions. If not you can use the quadratic formula to solve for the roots, solutions.
Answer:
Step-by-step explanation:
um you can answer them in many ways?
The set when z = -5 is {-27, -9, -5}
<h3>How to determine the set elements?</h3>
The set is given as:
{(4z-7,z-4,z) |z is any real number}
When z=-5, we have:
4z - 7 = 4(-5) - 7 = -27
z - 4 = -5 - 4 = -9
z = -5
So, we have:
{(4z-7,z-4,z) |z is any real number} ⇒ {-27, -9, -5}
Hence, the set when z = -5 is {-27, -9, -5}
Read more about sets at:
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The question is about types and number of soultions so you must use b^2-4ac which is the experssion under the root in the quadratic formula
so
if
b^2-4ac=0 then there is one real soultion
if
b^2-4ac<0 then there are two imaginary soultions that differ in the sign between them
if
b^2-4ac>0 then there are two real soultions
so a polynomial is written in the form
ax^2+bx+c=0
so a=-4
b=-4
c=-1
so b^2-4ac=16-16=0
so one real soultion is the answer you are looking
type:real
number:1
