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frez [133]
3 years ago
12

Determine the area of the rectangle below 15 times 2 1/2

Mathematics
2 answers:
AnnZ [28]3 years ago
8 0
It is 37.5 I am not 100 percent sure but this should be accurate
rjkz [21]3 years ago
5 0
37.5 square in/cm hope this helped!
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What is the equation of the line that passes through the point (3,6) and has a slope of -1/3
Mnenie [13.5K]

\Large\texttt{Answer\::}

Please consult the "Calculations" section of this ans .

\Large\texttt{Calculations\::}

The information we're given is below :

  • slope : -1/3
  • Point crossed by the line : (3, 6)

As per given information , we can do the following :

  • Write the line's equation in point slope form

Point - slope form looks like so :

y-y₁=m(x-x₁)

y-6=-1/3(x-3)

y-6=-1/3x+1

y=-1/3x+1+7

y=-1/3x+6

↑ \small\textsc{EQUATION OF THE LINE}

\small\textit{hope\:helpful~}

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2 years ago
This week, Marie trimmed 61% of the bushes in her yard. Katie trimmed 7/20 of the bushes in her yard. Who has trimmed a greater
NemiM [27]
Answer- Marie
7/20 = 0.35 = 35%
61% > 35%
5 0
1 year ago
PLS TO GOD HELP ME I GOTTA GET ALL OF THIS TURNED IN BY 11:59 IM PANICKING AND TIRED!!!!
nirvana33 [79]
It might be the first one or the second one. i said MIGHT!!
6 0
3 years ago
How to I write 1/8 without using a fraction bar ( it wants me to use exponents)
oksano4ka [1.4K]
2^-3

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6 0
3 years ago
Read 2 more answers
A marine biologist monitors the population of sunfish in a small lake. He records 800 sunfish in his first year, 600 sunfish in
Colt1911 [192]

Answer:

Let's use the variable y to represent the number of years passed since the first year.

The population on the first year (y = 0) was 800

The population in the second year (y = 1) was 600.

The ratio in which the population decreased can be calculated as:

R = 600/800 = 0.75

This means that 600 is the 75% of 800, this also means that between the first year and the second year, the population decreased by the 25%

Now let's look at the ratio between the second and third year (y = 2), the population the third year was 450

Now the ratio is:

R = 450/600 = 0.75

Same as before, then we already can see that the population will decrease by 25% each year.

The generic exponential decay equation is:

f(y) = A*(1  - r)^y

where:

A = initial population, in this case, is 800

y = our variable, in this case, represents the number of years

r = the amount that decreases per each unit of our variable, this must be written in decimal form. In this case, we know that the population decreases by 25% each year, and 25% written in decimal form is 0.25

Also, (1 - r) = R, where R is the ratio we found earlier.

To do this, we just divide 25% by 100% to get (25%/100% = 0.25)

Then our equation will be:

f(y) = 800*(1 - 0.25)^y

f(y) = 800*( 0.75)^y

1) We want to predict when the population will be 200.

to do this, we set:

f(y) = 200 = 800*( 0.75)^y

and solve it for y.

(200/800) = 0.75^y

(1/4) = 0.75^y

Now we can use the relationship:

Ln(a^x) = x*ln(a)

Then let's apply Ln( ) in both sides to get

ln(1/4) = y*ln(0.75)

ln(1/4)/ln(0.75) = y = 4.8 years.

This means that 4.8 years after the first year, the population will be around 200.

2) The population in the 25 th year (this is 24 years after the first one, so we take y = 24) is:

f(24) = 800*(0.75)^(24) = 0.80

Around this point, we will have no more sunfish in the lake.

7 0
3 years ago
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