You start by finding two points on the line. In this case, (-4,1) and (-2,2) will do.
To get from (-4,1) to (-2,2), you need to go “up 1, right 2” which gives you a slope of m = 1/2
Next you need the b-value, which comes from the y-intercept of (0,3). The b-value is 3.
Putting the slope and b-value into y=mx+b, you have y = 1/2 x + 3.
(x²+4x+3)/2(x²-10x+25)
the horizontal asymptote when the numerator and the denominator have the same degree (in this case, both of a degree of 2) is ration of the coefficients of the numerator and denominator. In this case, the coefficient for numerator x² is 1, and the coefficient for the denominator 2x² is 2, so the horizontal asymptote is y=1/2=0.5
the vertical asymptote is the x value. the denominator cannot be zero, if x²-10x+25=0, x would be 5, so the vertical asymptote is x=5
this is just one example. There can be others:
(2x²+5x+2)/[(4x-7)(x-5)] for another example, but this example has a second vertical asymptote 4x-7=0 =>x=7/4
Volume of the sphere is 4/3*pi*r^3
here, r is 11 yd.
volume = 4/3*pi*11^3
= 4/3*pi*1331
= 5575.28 yd^3
= 5575.3 yd^3
To find the residual I would subtract the predicted value from the measured value so for x-value 1 the residual would be 2-2.6 = -0.6
Answer:
the second one iy s very incorrect
