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Alexxandr [17]
3 years ago
11

90 596 round to the nearest 10000​

Mathematics
2 answers:
Kisachek [45]3 years ago
5 0
The Answer Would Be 90000.
Nikolay [14]3 years ago
3 0

Answer:

91 000

Step-by-step explanation:

596 rounds up to 600

600 is closer to 91 000 (it's 400 away) than to 90 000 (600 away).

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Which of the following equations is an example of inverse variation between variables x and y ?
Mademuasel [1]
The option C) y = 15/x

a) y = 15 x is an example of direct variation, with proportionality constant = 15

b) is an example of linear variation (it is the equation of a straight line that does not pass through the origin)

c) y = 15/x => y*x = 15 = constant which is the characteristic of an inverse relation

d) y = x/15 is an example of an inverse relation, with proportion constant = 1/15 
3 0
3 years ago
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For a certain​ drug, the rate of reaction in appropriate units is given by Upper R prime (t )equalsStartFraction 2 Over t plus 1
Tems11 [23]

Answer:

a) 8.13

b) 4.10

Step-by-step explanation:

Given the rate of reaction R'(t) = 2/t+1 + 1/√t+1

In order to get the total reaction R(t) to the drugs at this times, we need to first integrate the given function to get R(t)

On integrating R'(t)

∫ (2/t+1 + 1/√t+1)dt

In integration, k∫f'(x)/f(x) dx = 1/k ln(fx)+C where k is any constant.

∫ (2/t+1 + 1/√t+1)dt

= ∫ (2/t+1)dt+ ∫ (1/√t+1)dt

= 2∫ 1/t+1 dt +∫1/+(t+1)^1/2 dt

= 2ln(t+1) + 2(t+1)^1/2 + C

= 2ln(t+1) + 2√(t+1) + C

a) For total reactions from t = 1 to t = 12

When t = 1

R(1) = 2ln2 + 2√2

≈ 4.21

When t = 12

R(12) = 2ln13 + 2√13

≈ 12.34

R(12) - R(1) ≈ 12.34-4.21

≈ 8.13

Total reactions to the drugs over the period from t = 1 to t= 12 is approx 8.13.

b) For total reactions from t = 12 to t = 24

When t = 12

R(12) = 2ln13 + 2√13

≈ 12.34

When t = 24

R(24) = 2ln25 + 2√25

≈ 16.44

R(12) - R(1) ≈ 16.44-12.34

≈ 4.10

Total reactions to the drugs over the period from t = 12 to t= 24 is approx 4.10

3 0
3 years ago
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Gelneren [198K]

Answer:

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Step-by-step explanation:

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Answer:

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