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vladimir1956 [14]
2 years ago
7

What is 322 divided by 15 ?

Mathematics
2 answers:
agasfer [191]2 years ago
8 0
21 =322 ÷15   Divide the two numbers.
Murrr4er [49]2 years ago
3 0
   Your answer is 21 7/15
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Eva estimate the 475 songs will fit on her MP3 player. The actual amount of songs that fit is 380. Find percent error
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Answer: 20%

Step-by-step explanation: Let’s use the variable ‘x’ as the percent. You need to make an equation and fill in the blanks. ___ is ____% of ____. So 380 is x% of 475. Now solve the problem. 380/475 = x/100, cross multiply. Now you have 475x = 380 * 100 or 475x = 38000. Now divide each side by 475. Now you have, x = 80%. Now you subtract. 100% - 80%. AND YOU GET 20%

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Otis paints the interior of a home for $45 per hour plus $75 for supplies. Shireen paints the interior of a home for $55 per hou
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you should only make one equation:

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3 years ago
Read 2 more answers
Determine whether the set of vectors is a basis for ℛ3. Given the set of vectors , decide which of the following statements is t
schepotkina [342]

Answer:

(A) Set A is linearly independent and spans R^3. Set is a basis for R^3.

Step-by-Step Explanation

<u>Definition (Linear Independence)</u>

A set of vectors is said to be linearly independent if at least one of the vectors can be written as a linear combination of the others. The identity matrix is linearly independent.

<u>Definition (Span of a Set of Vectors)</u>

The Span of a set of vectors is the set of all linear combinations of the vectors.

<u>Definition (A Basis of a Subspace).</u>

A subset B of a vector space V is called a basis if: (1)B is linearly independent, and; (2) B is a spanning set of V.

Given the set of vectors  A= \left(\begin{array}{[c][c][c][c]}1 & 0 & 0 & 0\\ 0 & 1 & 0 & 1\\ 0 & 0 & 1 & 1\end{array} \right) , we are to decide which of the given statements is true:

In Matrix A= \left(\begin{array}{[c][c][c][c]}(1) & 0 & 0 & 0\\ 0 & (1) & 0 & 1\\ 0 & 0 & (1) & 1\end{array} \right) , the circled numbers are the pivots. There are 3 pivots in this case. By the theorem that The Row Rank=Column Rank of a Matrix, the column rank of A is 3. Thus there are 3 linearly independent columns of A and one linearly dependent column. R^3 has a dimension of 3, thus any 3 linearly independent vectors will span it. We conclude thus that the columns of A spans R^3.

Therefore Set A is linearly independent and spans R^3. Thus it is basis for R^3.

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