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koban [17]
4 years ago
14

Two baskets contain snacks. The basket contain 12 bags of peanuts, of which 5 are reduced sodium and 8 granola bars, of which 2

are reduced sodium. If you randomly select one snack from each basket, what is the probability that both snacks are reduced sodium and 1 snack is a bag of peanuts and the other is a granola bar?
Mathematics
1 answer:
Ghella [55]4 years ago
8 0
There are a total of 20 snacks in each bag.  We consider the probability of picking a bag of peanuts with reduced sodium and then a granola bar with reduced sodium, then multiply by 2 (because we could pick them in the other order).

There is a 5/20 chance of picking a sodium-reduced bag of peanuts first, and a 2/20 chance of picking a sodium-reduced granola bar next.  Thus, the chance of picking them together in that order is 5/20*2/20=10/400, or 1/40.  Because we could pick the snacks in either order, we multiply by two, for a result of a 1/20 probability.
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Triangle ABC maps to triangle A′B′C′ by a 90∘ rotation counterclockwise about the origin.
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Answer:

60 Units

Step-by-step explanation:

The length of AC does not change. Since the translation is a rotation, nothing about the size of the triangle should change. Meaning A'B'C' is still 60 units in length.

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The area of a square is 72. what is the longest straight line that can be drawn between any two points of the square
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The longest straight line that can be drawn between any two points of a square is the one that includes the points on the opposite corners of the squares. To determine the length of this straight line, we must first determine the length of the square's side. Since the area of the square can be calculated by taking the square of the side, then

s^2 = 72
s = 6 sqrt(2)

Then, using the Pythagorean theorem, we will find c (the longest side of straight line of the square) 

c^2 = a^2 + b^2

Upon substitution of the length of the square's side, we have
c^2 = (6 sqrt(2))^2 + (6 sqrt(2))^2
c^2 = 72+72
c = 72

The length of the longest line is 72.
 
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A box has a volume of 192 cubic inches, a length that is twice as long as its width, and a height that is 2 inches greater than
Volgvan

Answer:

Length = 8 inches

Width = 4 inches

Height = 6 inches

Step-by-step explanation:

Volume of the box = 192 cubic inches

Volume of a box = length × width × height

Let

Width = x

Length = 2x

Height = x + 2

Volume of a box = length × width × height

192 = 2x * x * (x + 2)

192 = 2x^2 (x + 2)

192 = 2x^3 + 4x^2

Divide through by 2

96 = x^3 + 2x^2

Subtract 96 from both sides

x ^3 + 2x^2 - 96 = 0

Factorise

(x - 4) (x^2 + 6x + 24) = 0

x^2 + 6x + 24 has no real x-value

So,

Divide both sides by (x^2 + 6x + 24).

0 ÷ (x^2 + 6x + 24) = 0

So,

(x - 4) = 0

x = 4

Width = x = 4 inches

Length = 2x

= 2(4)

= 8 inches

Height = x + 2

= 4 + 2

= 6 inches

Check:

Volume of a box = length × width × height

= (8 * 4 * 6) inches

= 192 inches

4 0
4 years ago
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