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koban [17]
3 years ago
14

Two baskets contain snacks. The basket contain 12 bags of peanuts, of which 5 are reduced sodium and 8 granola bars, of which 2

are reduced sodium. If you randomly select one snack from each basket, what is the probability that both snacks are reduced sodium and 1 snack is a bag of peanuts and the other is a granola bar?
Mathematics
1 answer:
Ghella [55]3 years ago
8 0
There are a total of 20 snacks in each bag.  We consider the probability of picking a bag of peanuts with reduced sodium and then a granola bar with reduced sodium, then multiply by 2 (because we could pick them in the other order).

There is a 5/20 chance of picking a sodium-reduced bag of peanuts first, and a 2/20 chance of picking a sodium-reduced granola bar next.  Thus, the chance of picking them together in that order is 5/20*2/20=10/400, or 1/40.  Because we could pick the snacks in either order, we multiply by two, for a result of a 1/20 probability.
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  • <em><u>average yearly salary of an individual whose final degree is a masters:</u></em><u> $ 66 thousand</u>

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Explanation:

You can set a system of equation using the following steps:

1. Name the variables:

  • average yearly salary of an individual whose final degree is a masters: x

  • average yearly salary of an individual whose final degree is a bachelors: y

2. Set the equations that relate the variables:

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        equation (1): x = 2y - 46

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         equation (2): x + y = 122

3. Solve the system:

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Substitute equation (1) into equation (2)

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Solve for y:

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Subsitute the value on y in equation 1, to find the value of x:

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Thus, the average yearly salary of a person with a masters degree is $ 66 thousand.

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