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3 years ago

8

Jack is a professional weightlifter. his personal lifting record was 125.8kg. at a weightlifting competition, he broke his own r

ecord by 540 g. what is his new record?

1 answer:

Softa [21]3 years ago

5 0

Answer:

126.34kg

Step-by-step explanation:

125.8+0.54=126.34kg

Convert 540 grams to kilograms` 0.54 kilograms, and add to the previous record

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An inverse variation function has a k value of 8. Which ordered pair is on the graph of the function?

Vinvika [58]

The points on the graph of the inverse variation are of the form:

(x, 8/x)

<h3>Which ordered pairs are on the graph of the function?</h3>

An inverse variation function is written as:

y = k/x.

Here we know that k = 8.

y = 8/x

Then the points (x, y) on the graph of the function are of the form:

(x, 8/x).

So evaluating in different values of x, we can get different points on the graph:

if x = 1, the point is (1, 8)
if x = 2, the point is (2, 4)
if x = 3, the point is (3, 8/3)
if x = 4, the point is (4, 2)

And so on.

If you want to learn more about inverse variations:

brainly.com/question/6499629

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2 years ago

Consider a uniform distribution from aequals4 to bequals29. (a) Find the probability that x lies between 7 and 27. (b) Find th

weeeeeb [17]

Answer:

a) 80% probability that x lies between 7 and 27.

b) 28% probability that x lies between 6 and 13.

c) 44% probability that x lies between 9 and 20.

d) 28% probability that x lies between 11 and 18.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value x between c and d, in which d is larger than c, is given by the following formula.

$P(c \leq x \leq d) = \frac{d - c}{b - a}$

Uniform distribution from a = 4 to b = 29

(a) Find the probability that x lies between 7 and 27.

So $c = 7, d = 27$

$P(7 \leq x \leq 27) = \frac{27 - 7}{29 - 4} = 0.8$

80% probability that x lies between 7 and 27.

(b) Find the probability that x lies between 6 and 13. 

So $c = 6, d = 13$

$P(6 \leq x \leq 13) = \frac{13 - 6}{29 - 4} = 0.28$

28% probability that x lies between 6 and 13.

(c) Find the probability that x lies between 9 and 20.

So $c = 9, d = 20$

$P(9 \leq x \leq 20) = \frac{20 - 9}{29 - 4} = 0.44$

44% probability that x lies between 9 and 20.

(d) Find the probability that x lies between 11 and 18.

So $c = 11, d = 18$

$P(11 \leq x \leq 18) = \frac{18 - 11}{29 - 4} = 0.28$

28% probability that x lies between 11 and 18.

3 0

3 years ago

HELP !!! Use the elimination method to solve the system of equations.

Dafna1 [17]

Answer:

C. (5, -3)

Step-by-step explanation:

4x + 3y = 11

x - y = 8 (multiply by 3) --> 3x - 3y = 24

4x + 3y = 11

3x - 3y = 24

---------------------add

7x = 35

x = 5

5 - y = 8

y = 5 - 8

y = -3

(5, -3)

3 0

3 years ago

Read 2 more answers

Write the equation for the quadratic function in standard form

Ede4ka [16]

Answer:

$y=x^2+6x+7$

Step-by-step explanation:

To write the quadratic in standard form, begin by writing it in vertex form

$y = a(x-h)^2+k$

Where (h,k) is the vertex of the parabola.

Here the vertex is (-3,-2). Substitute and write:

$y=a(x--3)^2+-2\\y=a(x+3)^2-2$

To find a, substitute one point (x,y) from the parabola into the equation and solve for a. Plug in (0,7) a y-intercept of the parabola.

$7=a((0)+3)^2-2\\7=a(3)^2-2\\7=9a-2\\9=9a\\1=a$

The vertex form of the equation is $y=(x+3)^2-2$ .

To write in standard form, convert vertex form through the distributive property.

$y=(x+3)^2-2\\y=(x^2+6x+9)-2\\y=x^2+6x+7$

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4 years ago

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lilavasa [31]

Answer:

<h2>=2⁵</h2><h2>it's option B 2⁵</h2><h2>(B) 2⁵ is the right option</h2>

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3 years ago