Ask question

Ask question

All categories

3 years ago

10

Does anyone know how to sovle this

1 answer:

Umnica [9.8K]3 years ago

7 0

The 2 interior angles add to the exterior angle
26+13=x
39=x

x=39°

because

remember, all angles add to 180
26+13+BCA=180
39+BCA=180
minus 39 both sides
BCA=141
look, we want x

BC is a striaign line which is 180
BCA+x=180
141+x=180
minus 141 from both sides
x=39°

You might be interested in

Please help.<br> Algebra.

iogann1982 [59]

The answer is b (2,-5)

4 0

3 years ago

Resolva a equação a seguir:<br> (x-3/2) + (2x-3/4) = (x²) + (x)-(17/2)

bagirrra123 [75]

X =(-8+√464)/-8=1-1/2√<span> 29 </span><span>= -1.693</span>

8 0

3 years ago

Which function passes through the points (2, 15) and (3, 26)?

igor_vitrenko [27]

<span>Which function passes through the points (2, 15) and (3, 26)?
</span>
Its B

7 0

3 years ago

Read 2 more answers

Lauren has finished 25% of the 120 push ups she needs to do for softball

Ilya [14]

Answer:

30 pushups

Step-by-step explanation:

25/100 = x/120

so, 120x25 = 100x

3000 = 100x

3000/100= x

x = 30

so, Lauren has completed 30 push-ups.

3 0

3 years ago

Find a power series representation for the function. (Assume a>0. Give your power series representation centered at x=0 .)

melamori03 [73]

Answer:

Step-by-step explanation:

Given that:

$f_x = \dfrac{x^2}{a^7-x^7}$

$= \dfrac{x^2}{a^7(1-\dfrac{x^7}{a^7})}$

$= \dfrac{x^2}{a^7}\Big(1-\dfrac{x^7}{a^7} \Big)^{-1}$

since $\Big((1-x)^{-1}= 1+x+x^2+x^3+...=\sum \limits ^{\infty}_{n=0}x^n\Big)$

Then, it implies that:

$\implies \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\Big(\dfrac{x}{a} \Big)^{^7} \Big)^n$

$= \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\dfrac{x}{a} \Big)^{^{7n}}$

$= \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\dfrac{x^{7n}}{a^{7n}} \Big)}$

$\mathbf{= \sum \limits ^{\infty}_{n=0} \dfrac{x^{7n+2}}{a^{7n+7}} }}$

7 0

3 years ago