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melamori03 [73]
3 years ago
14

What is the area of region enclosed by the graphs of y=0, x=6 , and y=1/3(x-3)+4

Mathematics
1 answer:
In-s [12.5K]3 years ago
3 0
It would be false b/c when you solve 0=5
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I have two proof questions and I don't really know how to do them.
goldfiish [28.3K]

\angle1\cong\angle2 corresponding angles, therefore

m∠1 = m∠2 → m∠2 = 130°

\angle2\cong\angle3 vertical angles, therefore

m∠2 = m∠3 → m∠3 = 130°


If ∠1 and ∠2 are complementary, then m∠1 + m∠2 = 90°.

If ∠2 and ∠3 are complementary, then m∠2 + m∠3 = 90°

Therfore

m\angle1 + m\angle2 = m\angle2 + m\angle3\qquad|\text{subtract}\ m\angle2\ \text{ from both sides}\\\\m\angle1 = m\angle3\to\angle1\cong\angle3

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1 + 0.09 = 1.09

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The original price of the in-line skates was $98.1
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Which expression is equivalent to the given expression?
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