Answer:
3.1
Step-by-step explanation:
because u have to take away the - sign if it is two negatives :3
Answer:
Step-by-step explanation:
Let x ft be the length of the fence and y ft be the width of the fence.
1. The length of the habitat should be at least 80 feet, then
2. The perimeter of the habitat should be no more than 300 feet. The perimeter of the fences 2x+2y ft, then
3. The system of inequalities that represent the model is
The graph of these inequalities is attached.
Two possible solutions are
1. x=100 ft, y=20 ft (100≥80 and 2·100+2·20=240≤300);
2. x=110 ft, y=30 ft (110≥80 and 2·110+2·30=280≤300).
A)
![\bf 1990-1910=80\leftarrow t \\\\\\ P(t)=8000(2)^{-\frac{t}{29}}\implies P(80)=8000(2)^{-\frac{80}{29}} \\\\\\ P(80)=8000\cdot \cfrac{1}{2^{\frac{80}{29}}}\implies P(80)=\cfrac{8000}{\sqrt[29]{2^{80}}}](https://tex.z-dn.net/?f=%5Cbf%201990-1910%3D80%5Cleftarrow%20t%0A%5C%5C%5C%5C%5C%5C%0AP%28t%29%3D8000%282%29%5E%7B-%5Cfrac%7Bt%7D%7B29%7D%7D%5Cimplies%20P%2880%29%3D8000%282%29%5E%7B-%5Cfrac%7B80%7D%7B29%7D%7D%0A%5C%5C%5C%5C%5C%5C%0AP%2880%29%3D8000%5Ccdot%20%5Ccfrac%7B1%7D%7B2%5E%7B%5Cfrac%7B80%7D%7B29%7D%7D%7D%5Cimplies%20P%2880%29%3D%5Ccfrac%7B8000%7D%7B%5Csqrt%5B29%5D%7B2%5E%7B80%7D%7D%7D)
and surely you know how much that is.
b)

since in 1910 t = 0, 174 years later from 1910, is 2084, so in 2084 they'll be 125 exactly, so the next year, 2085, will then be the first year they'd fall under that.
Hello guys I am new here and I don't know how to answer your question