Answer:
Step-by-step explanation:
Directions
- Draw a circle
- Dear a chord with a length of 24 inside the circle. You just have to label it as 24
- Draw a radius that is perpendicular and a bisector through the chord
- Draw a radius that is from the center of the circle to one end of the chord.
- Label where the perpendicular radius to the chord intersect. Call it E.
- You should get something that looks like the diagram below. The only thing you have to do is put in the point E which is the midpoint of CB.
Givens
AC = 13 inches Given
CB = 24 inches Given
CE = 12 inches Construction and property of a midpoint.
So what we have now is a right triangle (ACE) with the right angle at E.
What we seek is AE
Formula
AC^2 = CE^2 + AE^2
13^2 = 12^2 + AE^2
169 = 144 + AE^2 Subtract 144 from both sides.
169 - 144 = 144-144 + AE^2 Combine
25 = AE^2 Take the square root of both sides
√25 = √AE^2
5 = AE
Answer
The 24 inch chord is 5 inches from the center of the circle.
3! =3 x 2 x 1 = 6
Y!= Y x (y-1) x ... x 1=
Actually they want you to simplify the problem.
The problems answer is:
30 goes into 15; 2 times.
Final Answer: 2
Stokes' theorem says the integral of the curl of
over a surface
with boundary
is equal to the integral of
along the boundary. In other words, the flux of the curl of the vector field is equal to the circulation of the field, such that

We have


Parameterize the ellipse
by

with
and
.
Take the normal vector to
to be

Then the flux of the curl is

C=2(3.14)(radius)
c=2(3.14)(250)
c= 1570