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3 years ago

the stove and the freezer weigh at least 260kg. the stove weighs 115 kg. How much would the freezer weigh?

Mathematics

2 answers:

Aleks [24]3 years ago

7 0

About 145 I gonna guess I dont know if that's right

saveliy_v [14]3 years ago

7 0

Answer:

freezer weight = at least 145 kg

Step-by-step explanation:

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Harmons and Smiths are having a sale on apples. Harmons charges $1.25 for 5 apples. Smiths charges $2.04 for 6 apples. Find the

8090 [49]

Answer:

0.09

Step-by-step explanation:

Divide 1.25 by 5 which is 0.25, and 2.04 by 6 which is 0.34

Then subtract the answers 0.34-0.25=0.09

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3 years ago

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Sedbober [7]

I like A as the best one

420 = 100*price - (fixed costs)
220 = 60*price - (fixed costs)

If we subtract one from the other one, we get 200 = 40*price, price = 5
that said, fixed costs are 500 - 420 = 80

Now if we move -220 to the right in Answer A, we'll get:

y = 5x -300 + 220 = 5x - 80

So it looks like A describes the model best

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3 years ago

Changing Bases to Evaluate Logarithms in Exercise, use the change-of-base formula and a calculator to evaluate the logarithm. Se

son4ous [18]

Answer:

The question is incomplete, the complete question is "Changing Bases to Evaluate Logarithms in Exercise, use the change-of-base formula and a calculator to evaluate the logarithm. See Example 9. $log_{4}7$ .

$log_{4}7=1.404\\$

Step-by-step explanation:

From the general properties or laws of logarithm, we have the

$log_{a}b=\frac{logb}{loga} \\$

where both log are now express in the natural logarithm base.

i.e $log_{a}b=\frac{lnb}{lna}\\$

hence we can express our $log_{4}7=\frac{ln7}{ln4} \\$ .

the value of ln7 is 1.9459 and ln4 is 1.3863

Hence $log_{4}7=\frac{ln7}{ln4}=\frac{1.9459}{1.3863}\\$ .

$log_{4}7=1.404\\$

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Lisa [10]

The answer is x= 3,8

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3 years ago

the length of a rectangle is 3 units shorter than one -third of the width, x. Which expression represents the perimeter of the r

Mariana [72]

Answer:

A) $\frac{8}{3} x - 6$

Step-by-step explanation:

Let the width of the rectangle be x units.

$\therefore \: length \: of \: rectangle = \frac{1}{3} x - 3 \\ Perimeter \: of \: rectangle = 2(l + w) \\ = 2 \bigg( \frac{1}{3} x - 3 + x \bigg)\\ = 2 \bigg( x + \frac{1}{3} x - 3 \bigg)\\ = 2 \bigg( \frac{3x + x}{3} - 3 \bigg)\\ = 2 \bigg( \frac{4x}{3} - 3 \bigg) \\ = 2 \bigg( \frac{4x}{3} - 3 \bigg) \\ = \frac{2 \times 4x}{3} -2 \times 3 \\ \purple{ \bold{{Perimeter \: of \: rectangle = \frac{8}{3} x - 6}}}$

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3 years ago