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Dimas [21]
2 years ago
10

the stove and the freezer weigh at least 260kg. the stove weighs 115 kg. How much would the freezer weigh?

Mathematics
2 answers:
Aleks [24]2 years ago
7 0
About 145 I gonna guess I dont know if that's right
saveliy_v [14]2 years ago
7 0

Answer:

freezer weight = at least 145 kg

Step-by-step explanation:


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What is the sine value of 7 pi over 6? negative square root 3 over 2 square root 3 over 2 negative 1 over 2 1 over 2?
djverab [1.8K]
First thing to do is to change the radians to degrees so it's easier to determine our angle and where it lies in the coordinate plane.  \frac{7 \pi }{6} * \frac{180}{ \pi }=210.  If we sweep out a 210 degree angle, we end up in the third quadrant, with a 30 degree angle.  In this quadrant, x and y are both negative, but the hypotenuse, no matter where it is, will never ever be negative.  So the side across from the 30 degree reference angle is -1, and the hypotenuse is 2, so the sine of this angle, opposite over hypotenuse, is -1/2
6 0
3 years ago
Read 2 more answers
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Dafna11 [192]

Answer:

3.6 divided by 3 = 1.2 so 1.2 yards of material can be used on each skirt.

Step-by-step explanation:

4 0
3 years ago
A piggy bank contains pennies, nickels, and dimes. The number of dimes is 15 more than the number of nickels, and there are 140
amm1812

Answer:

Option D is correct.

There are 34 nickels in the piggy bank.

Step-by-step explanation:

A piggy bank contains pennies, nickels and dimes.

Let the number of pennies be p

Let the number of nickels be n

Let the number of dimes be d

Also, note that 1 penny = $0.01

1 nickel = $0.05

1 dime = $0.10

- The number of dimes is 15 more than the number of nickels.

d = 15 + n

- There are 140 coins altogether totaling $7.17.

p + n + d = 140

0.01p + 0.05n + 0.1d = 7.17

Bringing the 3 equations together

d = 15 + n (eqn 1)

p + n + d = 140 (eqn 2)

0.01p + 0.05n + 0.1d = 7.17 (eqn 3)

Substitute (eqn 1) into (eqn 2)

p + n + d = 140

p + n + (15 + n) = 140

p + 2n + 15 = 140

p = 140 - 15 - 2n = 125 - 2n

p = 125 - 2n (eqn 4)

Substitute (eqn 1) and (eqn 4) into (eqn 3)

0.01p + 0.05n + 0.1d = 7.17

0.01(125 - 2n) + 0.05n + 0.1(15 + n) = 71.7

1.25 - 0.02n + 0.05n + 1.5 + 0.1n = 7.17

0.1n + 0.05n - 0.02n + 1.5 + 1.25 = 7.17

0.13n + 2.75 = 7.17

0.13n = 7.17 - 2.75 = 4.42

0.13n = 4.42

n = (4.42/0.13) = 34

d = 15 + n = 15 + 34 = 49

p = 125 -2n = 125 - (2×34) = 125 - 68 = 57

Hence, there are 57 pennies, 34 nickels and 49 dimes in the piggy bank.

Hope this Helps!!!

7 0
3 years ago
The stock price for International Business Machines (IBM) historically has followed an approximately normal distribution (when a
olganol [36]

Answer:

0.494 is the probability that on a selected day the stock price is between $186.26 and $192.47.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = $188.876

Standard Deviation, σ = $4.6412

We are given that the distribution of stock price is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(stock price is between $186.26 and $192.47)

P(186.26 \leq x \leq 192.47) = P(\displaystyle\frac{186.26 - 188.876}{4.6412} \leq z \leq \displaystyle\frac{192.47-188.876}{4.6412}) = P(-0.5636 \leq z \leq 0.7743)\\\\= P(z \leq 0.7743) - P(z < -0.5636)\\= 0.781 - 0.287 = 0.494 = 49.4\%

P(186.26 \leq x \leq 192.47) = 49.4\%

0.494 is the probability that on a selected day the stock price is between $186.26 and $192.47.

5 0
3 years ago
1. -7-(-2) *
Morgarella [4.7K]
1. -7-(-2)
= -7+2= -5

2. 5-(-3)
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3. -6-4
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3 years ago
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