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sergiy2304 [10]
3 years ago
7

In the diagram below, the perimeter of the triangle is equal to the perimeter of the square. What is the length of a side of the

square?

Mathematics
1 answer:
kondaur [170]3 years ago
3 0

The perimeter of each is the sum of the lengths of its sides.

Triangle Perimeter = 16 + 4x-3 +3x = 7x+13

Square Perimeter = 2x +2x +2x +2x = 8x

If these are equal, you have

7x+13=8x\\\\13=x\qquad \mbox{subtract 7x}\\\\26=2x\qquad \mbox{multiply by 2}

The length of a side of the square is 26 units.

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Aaron says that all
Softa [21]

Answer:

NO

Step-by-step explanation:

Look at the figure attached below, we know that the area of the cone is the sum of area of circle part and cone part of the figure.

to find the surface area of the cone, first measure the radius of the base and find the area of the circle part by  formula \pi r^2. Then measure the side (slant height) length of the cone part and find the area of the cone part by the formula \pi rl.

Now the surface area of the cone is circumference of the circle plus area of the cone part.

i.e. surface\ Area\ of\ the\ cone=\pi r^{2}+\pi rl

From the above discussion we concluded that surface area of the cone does not depend only on the circumference of the base but also we need side length of the cone part as well thus <em>all  cones with a base circumference of 8 inches  will </em><em>not </em><em>have the same surface area.</em>

<em />

5 0
3 years ago
Need help −5x = 15 !!!!!!!!!!!!
-BARSIC- [3]

Answer:

x = -3

Step-by-step explanation:

−5x = 15

-5x/-5 = 15/-5

x = -3

4 0
3 years ago
Read 2 more answers
Number of real solutions?<br><br> 8x^2 - 11x = -3<br><br> -4x^2 - 4 = 8x
Anna71 [15]

(1) ANSWER

x =  \frac{3}{8}  \: or \:  x = 1

(2) ANSWER

x =  - 1

3 0
3 years ago
Find the x-coordinates where f '(x) = 0 for f(x) = 2x - sin(2x) in the interval [0, 2π].
Serggg [28]

Answer:

The x-coordinates where f '(x) = 0 for f(x) = 2x - sin(2x) in the interval [0, 2π] are: x=0, π, and 2π.


Step-by-step explanation:

f(x)=2x-sin(2x)

f'(x)=[f(x)]'

f'(x)=[2x-sin(2x)]'

f'(x)=(2x)'-[sin(2x)]'

f'(x)=2-cos(2x) (2x)'

f'(x)=2-cos(2x) (2)

f'(x)=2-2 cos(2x)


f'(x)=0, then:

2-2 cos(2x)=0

Solving for x. First solving for cos(2x): Subtracting 2 from both sides of the equation:

2-2 cos(2x)-2=0-2

-2 cos(2x)=-2

Dividing both sides of the equation by -2:

-2 cos(2x) / (-2)=-2 / (-2)

cos(2x)=1

If cos(2x)=1, then:

2x=2nπ

Dividing both sides of the equation by 2:

2x/2=2nπ/2

x=nπ


If n=-1→x=-1π→x=-π, and -π is not in the interval [0,2π], then x=-π is not in the solution.

If n=0→x=0π→x=0, and 0 is in the interval [0,2π], then x=0 is in the solution.

If n=1→x=1π→x=π, and π is in the interval [0,2π], then x=π is in the solution.

If n=2→x=2π, and 2π is in the interval [0,2π], then x=2π is in the solution.

If n=3→x=3π, and 3π is not in the interval [0,2π], then x=2π is not in the solution.


Solution: x=0, π, and 2π.

5 0
3 years ago
what algebraic expression must be added to the sum of 3x squared + 4x + 8 and 2x squared -6x + 3 to give 9x squared -2x - 5 as t
gregori [183]
<span>3x^2 + 4x + 8 + 2x^2 - 6x + 3 to give result as 9x^2 -2x - 5


</span>3x^2 + 4x + 8 + 2x^2 - 6x + 3 
= 5x^2 - 2x + 11

so

9x^2 -2x - 5 - (5x^2 - 2x + 11)
= 9x^2 -2x - 5 -  5x^2 +  2x - 11
= 4x^2 -16

answer

expression (4x^2 -16) must be added to the sum of (3x^2 + 4x + 8) and (2x^2 - 6x + 3) to give the result as (9x^2 - 2x - 5)
3 0
3 years ago
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