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nexus9112 [7]
3 years ago
13

Determine algebraically whether the function is even, odd, or neither even nor odd.

Mathematics
1 answer:
sdas [7]3 years ago
3 0
It is an even function
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Laura is training to run a race. She keeps track of the number of miles she runs. She has been training for 5 weeks, and she has
V125BC [204]

Answer:

8 miles per week!

Step-by-step explanation:

40 miles / 5 weeks = 8!

so it would be 8 miles per week.

i hope this helps!!

4 0
2 years ago
The radius of the base of a cylinder is 10 centimeters and its height is 20 centimeters A cone is used to fill the cylinder with
rewona [7]

Answer:

24 times

Step-by-step explanation:

cone is used to fill cylinder

conevolume times x=cylindervolume

so

x=cylinderv/conev

cylinderv=hpir^2

conevolume=1/3hpir^2

cylinder:

v=hpir^2

r=10

h=20

v=20*pi*10^2=2000π

cone=1/3hπr²

r=5

h=10

v=1/3(10)π5²=250π/3

volume of cylinder ÷ volume of cone

= 2000π ÷ (250π÷3)

= 6000π ÷ 250π

= 600÷25

= 24

please mark me brainliest

6 0
4 years ago
A bowling alley charges x dollars per guest and a fixed $50 rental fee for parties. Which equation represents the total cost,y,
dmitriy555 [2]

Answer:

y = 9x + 50

Step-by-step explanation:

No choices but an equation would be:

y = 9x + 50

4 0
4 years ago
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crimeas [40]

Answer:

..............................................yes

Step-by-step explanation:

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5 0
3 years ago
Internet Pricing An Internet Service Provider (ISP) offers its customers three options:
Mama L [17]

Answer:

(b)$29.62

(c)$5.73

Step-by-step explanation:

Basic: Standard internet for everyday needs, at $24.95 per month.

Premium: Fast internet speeds for streaming video and downloading music, at $30.95 per month.

Ultra: Super-fast internet speeds for online gaming at $40.95 per month.

Let the number of customers on Ultra=x; therefore:

Number of Premium customers =2x

Number of Basic customers =3x

Total=x+2x+3x=6x

P(Ultra)=\dfrac{x}{6x}=\dfrac{1}{6}  \\P(Premium)=\dfrac{2x}{6x}=\dfrac{1}{3}\\P(Basic)=\dfrac{3x}{6x}=\dfrac{1}{2}

(a)X=Monthly fee paid by a randomly selected customer.

Therefore, the probability distribution of X is given as:

\left|\begin{array}{c|c}X&P(X)\\---&---\\\$24.95&3/6\\\$30.95&2/6\\\$40.95&1/6\end{array}\right|

(b)Average Monthly Revenue per customer

Mean,

\mu=(\$24.95 \times 3/6)+(\$30.95 \times 2/6)+(\$40.95 \times 1/6)\\=\$29.62

(c)Standard Deviation

\left|\begin{array}{c|c|c|c|c}x&P(x)&x-\mu &(x-\mu)^2&(x-\mu)^2P(x)\\-----&-----&----&----&-----\\\$24.95&3/6&-4.67&21.8089&10.9045\\\$30.95&2/6&1.33&1.7689&0.5896\\\$40.95&1/6&11.33&128.3689&21.3948\\-----&-----&----&----&-----\\&&&&32.8889\end{array}\right|

\text{Standard Deviation}=\sqrt{(x-\mu)^2P(x)}\\=\sqrt{32.8889} \\ \sigma=\$5.73

4 0
3 years ago
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