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3 years ago

Megan Hikes 15.12 mi in 6.3 hours. If Megan hike the same number of miles each hour, how many miles did she hike each hour.

Mathematics

2 answers:

rodikova [14]3 years ago

6 0

Answer:

The answer is 2.4 Miles per hour

Step-by-step explanation:

15.12 divided by 6.3= 2.4 MPH

aev [14]3 years ago

5 0

2.4 mile per hour
1.divide miles by hours
2.get answer
3.check by multiplying the hours by the 2.4

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Work out 10.3 % of 853.93 km Give your answer rounded to 2 DP.

Vilka [71]

Answer: 87.95

Step-by-step explanation: 10.3% of 853.93

10.3%= 0.103

So you would do 0.103 times 853.93=87.95479 round that to 2 Dp. You get 87.95

7 0

3 years ago

Halla el conjunto solución del siguiente sistema de ecuaciones aplicando el método de reducción: 2x + 3y = 8 x – 5y = 6

AysviL [449]

Answer:

x = 7.535 and y = 0.307

Step-by-step explanation:

Given that,

Two equations,

2x + 3y = 8 ...(1)

x – 5y = 6....(2)

Multiply equation (2) by -2.

-2x + 10y = -12....(3)

Now, adding equations (1) and (2),

2x + 3y -2x + 10y = 8-12

13y = 4

y = 0.307

Put the value of y in equation (2).

x – 5(0.307) = 6

x = 6 + 1.535

x = 7.535

So, the solutions of the given equation are x = 7.535 and y = 0.307.

4 0

2 years ago

you currently have 24 credit hours and a 2.8 gpa you need a 3.0 gpa to get into the college. if you are taking a 16 credit hours

Juliette [100K]

Answer:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

Step-by-step explanation:

For this case we know that the currently mean is 2.8 and is given by:

$\bar X = \frac{\sum_{i=1}^n w_i *X_i }{24} = 2.8$

Where $w_i$ represent the number of credits and $X_i$ the grade for each subject. From this case we can find the following sum:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

6 0

3 years ago

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g100num [7]

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2 years ago

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