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likoan [24]
3 years ago
5

A team of scientists estimate the current number of butterflies in a park to be 20 thousand. The butterfly population is expecte

d to increase at a rate of 4% per year. Which equation models the number of butterflies, in thousands, in the park after n years? A. 0.04(20)n B. 20(1.04)n C. 1.04(20)n D. 20(0.04)n
Mathematics
1 answer:
lesantik [10]3 years ago
3 0
C. seems more plausible
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There is a mound of g pounds of gravel in a quarry. Throughout the day, 300 pounds of gravel are added to the mound. Two orders
galina1969 [7]

Answer:

g+300-700-700=1500, g=2600

Step-by-step explanation:

At the start of the day there are g pounds of gravel in the quarry.

Then it says that there were 300 pounds added to the mound, so at this point the pounds of gravel in the mound are now g+300.

Then two orders of 700 pounds are sold and removed from the mound. That means they removed 700 pounds from the mound 2 times. Therefore at this point the pounds of gravel in the mound are now g+300-700-700.

Then it says that at this point, the amount of pounds in the mound are 1500.  Hence we get

g+300-700-700=1500

To solve for g we just add 700 two times to both sides of the equation, and subtract 300 from both sides of the equation, getting:

g+300-700-700+700+700-300=1500+700+700-300

And so g=2600

4 0
3 years ago
Rewrite y=(0.9)^t−4 in the form y=a(1+r)^t or y=a(1−r)^t to determine whether it represents exponential growth or exponential de
son4ous [18]

Answer:

its

Step-by-step explanation:

13+(4^3)

6 0
3 years ago
HELP MEE BRAINLIEST PLZZZZ!!!!
wel

The 3rd one

This is because in the graph it’s looking for numbers 70-79 but only with 2 numbers and the 3rd is the only one that fits in the description.

8 0
3 years ago
3/7•d=9/14 in this<br> Problem you want to find what d equals
sertanlavr [38]
<u>→ Chapter : Fractions ←</u>
<u><em>≡ We know that:</em></u>
⇔ (\frac{a}{b}) \div (\frac{c}{d})=(\frac{a}{b}) \times (\frac{d}{c})

<u><em>≡ Solution:</em></u>
⇒ (\frac{3}{7}) \times (d)=\frac{9}{14}
⇒ d=(\frac{9}{14}) \div (\frac{3}{7})
⇒ d=(\frac{9}{14}) \times (\frac{7}{3})
∴ \boxed{\frac{3}{2}}
7 0
3 years ago
Using the equation of the line (y = 0.5x + 79), what would be the melting point of dna with 50% gc content? enter your answer as
steposvetlana [31]
We have the equation of the line as follows:
y = 0.5x + 79

We want to calculate the melting point (the y value) of DNA  with 50% gc content (the x value).
The gc content represents the value of x in the equation, so to calculate the melting point (y), we will simply substitute the x with 50 in the equation of the line as follows:
melting point = 0.5(50) + 79 = 25 + 79 = 104 degrees
4 0
3 years ago
Read 2 more answers
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