Answer:
<u>The correct answer is that a student have to score 1.41 standard deviations above the mean to be publicly recognized.</u>
Step-by-step explanation:
For answering the question, we don't know the score mean of the National Financial Capability Challenge Exam and neither the population or number of students who take the exam. The only information provided is that the public recognition in this normal distribution is only for students that scores in the top 8%. In other words for students above 92% of the population.
With this information, we can go to a Z Score Table and check that for being on the top 8% (above the 92% of any population), your result must be 1.405 standard deviations above the mean.
<u>Rounding the answer to 2 decimal places, it's 1.41 standard deviations above the mean.</u>
Do recall that squaring and the *radical sign* cancel each other out... like so:(

)

= a
When you put it that way, it isn't enough :P
(

)

= a
(

)

=?
so you start with
(

)

=

8x+1=25 <-- subtract 1 to both sides
8x=24 <- divide 8 to both sides
x= 3
To find out if it's an extraneous solution ask yourself: It mustn't result in a radical that I like to call... 'illegal'. Plug it into the radicand 8x+1 and make sure you get something that is not a negative number.... so, DO you get a negative number when you plug in x = 3 into the radicand?
(extraneous solution is a invalid solution)
x=3 not extraneous
Answer:
p = 2.7x - 20
p(90) = $223
Step-by-step explanation:
revenue → f(x) = 3x ,where x is the number of downloads.
the statement “Your profit p is $20 less than 90% of the revenue for x downloads”
<u><em>means</em></u>

<u><em>means</em></u>
<u><em></em></u>
<u><em>means</em></u>

<u><em>means</em></u>

<u><em>means</em></u>

………………………………
the profit for 90 downloads :
= p(90)
= 2.7×(90) - 20
= $223
-|-10|-(-10)
A negative outside of the “ | “ means that one number inside will be negative . -10-(-10)
An imaginary | will “appear” in between the two negative signs or it will turn into an addition sign.
-10+10
A positive subtracts negatives from the negative number. The answer is 0
I hope this helped.