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3 years ago

If a man is 3 ft tall and casts an 8 foot shadow then how tall is a cat that casts a 18 inch shadowv

1 answer:

6 0

18 inch = 3/2 ft
$\frac{ \frac{3}{2} \times 3 }{8} \\ = \frac{ \frac{9}{2} }{8} \\ = \frac{9}{2} \times \frac{1}{8} \\ = \frac{9}{16}$
Cat tall 9/16 ft = 6.75 inch

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$83 + n$

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The sum of 83 and a number would be $83 + n$ as an expression, where $n$ is "said number".

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3 years ago

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3 years ago

Which graph represents Y as a function of x?

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Step-by-step explanation:

a "function" gives every x value exactly one y value.

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that is what I am talking about.

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1 year ago

How many L are in 1,500mL

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3 years ago

Assume that the wavelengths of photosynthetically active radiations (PAR) are uniformly distributed at integer nanometers in the

Lana71 [14]

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$\mathbb P(X=x)=\begin{cases}\dfrac1{26}&\text{for }630\le x\le655,x\in\mathbb Z\\\\0&\text{otherwise}\end{cases}$

The mean (expected value) is given by

$\mathbb E(X)=\displaystyle\sum_xx\mathbb P(X=x)$

and the variance by

$\mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2$

First, the mean:

$\mathbb E(X)=\displaystyle\sum_{x=630}^{655}x\mathbb P(X=x)=\frac1{26}\sum_{x=630}^{655}x$
$\mathbb E(X)=\dfrac{16705}{26}\approx643$

(rounded up from an exact value of 642.5)

Now for the variance:

$\mathbb E(X^2)=\displaystyle\sum_xx^2\mathbb P(X=x)=\frac1{26}\sum_{x=630}^{655}x^2$
$\mathbb E(X^2)=412862.5$

Meanwhile, $\mathbb E(X)^2=642.5^2=412806$ , which gives a total variance of

$\mathbb V(X)=412862.5-412806\approx57$

(rounded up from 56.5)

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2 years ago