The counter-current is the process that occurs in the excretory system. The limbs become the multiplier because of the active transport of the electrolytes that move out.
<h3>What is the loop of Henle?</h3>
The loop of Henle is the part of the excretory system and part of the nephron. It functions in minimizing the water loss in the excretion of urine. There are descending and ascending loops present.
The ascending loop is impermeable to water but permeable to the electrolytes, and hence the concentration of the sodium, potassium, and chloride ions are actively pumped. This makes the solution more concentrated in the ascending loop.
Therefore, the electrolyte concentration results in active transport.
Learn more about the loop of Henle here:
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When it switches to a lower orbital, the atom emits energy in the form of photons.
This segment is called a gene
Given the reaction 2Pb(s)+O2(g)= 2PbO(s) and a reactant amount of 451.4 grams, we are asked for the yield of the reaction. The amount of lead present produces 451.4/207.2 *( 2/2) *(223.2) via 100% conversion, 486.26 grams lead (II) oxide. hence the percent yield is 356.7g /<span>486.26 g or equal to 73.35 percent</span>
N₂ : limiting reactant
H₂ : excess reactant
<h3>Further e
xplanation</h3>
Given
mass of N₂ = 100 g
mass of H₂ = 100 g
Required
Limiting reactant
Excess reactant
Solution
Reaction
<em>N₂+3H₂⇒2NH₃</em>
mol N₂(MW=28 g/mol) :
mol H₂(MW= 2 g/mol) :
A method that can be used to find limiting reactants is to divide the number of moles of known substances by their respective coefficients, and small or exhausted reactans become a limiting reactants
From the equation, mol ratio N₂ : H₂ = 1 : 3, so :
N₂ becomes a limiting reactant (smaller ratio) and H₂ is the excess reactant
