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DaniilM [7]
3 years ago
12

In the following reaction, 451.4g of lead reacts with excess oxygen forming 356.7g of lead (II) oxide. Calculate the percent yie

ld of the reaction. 2Pb(s)+O2(g)= 2PbO(s)
Chemistry
1 answer:
Sholpan [36]3 years ago
8 0
Given the reaction 2Pb(s)+O2(g)= 2PbO(s) and a reactant amount of 451.4 grams, we are asked for the yield of the reaction. The amount of lead present produces 451.4/207.2 *( 2/2) *(223.2) via 100% conversion, 486.26 grams lead (II) oxide. hence the percent yield is 356.7g /<span>486.26 g or equal to 73.35 percent</span>
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What is the ph of with a 4.6 x 10-6 M hydroxide ion concentration?
Lunna [17]
<h3>Answer:</h3>

pH = 8.66

<h3>Explanation:</h3>
  • The pH refers to the acidity or alkalinity of a solution.
  • It is calculated by getting the negative logarithm of Hydrogen ions concentration.
  • pH=-log[H⁺]

In this case;

we are given [OH⁻] as 4.6 x 10^-6 M

We are required to calculate the pH

We need to know that;

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To get the pH we can calculate the pOH first,

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4 0
3 years ago
A compound is found to be 30.45% n and 69.55 % o by mass. if 1.63 g of this compound occupy 389 ml at 0.00°c and 775 mm hg, what
Charra [1.4K]
1) mass composition

N: 30.45%
O: 69.55%
   -----------
   100.00%

2) molar composition

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O: 69.55 / 16.00 = 4.346875

4) Find the smallest molar proportion

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9) Find how many times the mass of the empirical formula is contained in the molar mass

92.14 / 46.00 = 2.00

10) Multiply the subscripts of the empirical formula by the number found in the previous step

=> N2O4

Answer: N2O4
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