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SSSSS [86.1K]
3 years ago
5

Lisa walks at a speed of 3 25 miles per hour for 1 5 hours How many miles does she walk in all?

Mathematics
2 answers:
Blababa [14]3 years ago
7 0

Answer:

I think it might be 21.6 or just 21

Nookie1986 [14]3 years ago
5 0

Answer:

For 1.5 hours of walking, she will walk a total of 4.875 miles.

Step-by-step explanation:

You multiply how long she was walking for by how many miles she can walk per hour, to find the total answer of how many miles she will walk.

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Find the length of side b in the right triangle below use the calculator to estimate the square root to one decimal place.
Readme [11.4K]

Answer:

<h2>b = 16.7</h2>

Step-by-step explanation:

Since the triangle is a right angled triangle we can use Pythagoras theorem to find the missing side b

Using Pythagoras theorem we have

a² = b² + c²

where

a is the hypotenuse

Substituting the values into the above formula we have

<h3>{19}^{2}  =  {9}^{2}  +  {b}^{2}  \\  {b}^{2}  =  {19}^{2}   -   {9}^{2}  \\  {b} =  \sqrt{ {19}^{2}   -   {9}^{2} }  \\ b =  \sqrt{361  -  81}  \\ b =  \sqrt{280}  \\ \:  \:  \:  \:  \:  \:  b = 2 \sqrt{70}  \:  \:  \:  \:  \:  \:  \\ \:  \:  \:  \:  \:  \:  \:  b = 16.73320</h3>

We have the final answer as

<h3>b = 16.7 to one decimal place</h3>

Hope this helps you

5 0
3 years ago
A pizza parlor offers a choice of 16 different toppings. How many 6-topping pizzas are possible?
Anvisha [2.4K]

120 is the answer. Good Luck

4 0
2 years ago
Read 2 more answers
You wish to prove that three propositions p1, p2, and p3 are equivalent. will it suffice to show that p1 --&gt; p2, p2 --&gt; p3
kompoz [17]

Answer:

It is sufficient to prove that  p_1\implies p_2, p_2\implies p_3, p_3\implies p_1

Step-by-step explanation:

The propositions p_1,p_2,p_3 being equivalent means they should always have the same truth value. If one of them is true, then all of them must be true. And if one of them is false, then all of them must be false.

Suppose we've proven that p_1\implies p_2, p_2\implies p_3, p_3\implies p_1 (call these first, second and third implications).

If p_1 was true, then by the first implication that we proved, it would follow that p_2 is also true. And then by the second implication that we prove it would follow then that p_3 is also true. Therefore the three of them would be true. Notice the reasoning would have been the same if we had started assuming that the one that was true was either p_2~or~p_3. So one of them being true makes all of them be true.

On the other hand, if p_1 was false, then by the third implication that we proved, it would follow that p_3 has to be false (otherwise p_1 would have to be true, which would be a contradiction). And then, since p_3 is false, by the second implication that we proved it would follow that p_2 is false (otherwise p_3 would have to be true, which would be a contradiction). Therefore the three of them would be false. Notice the reasoning would have been the same if we had started assuming that the one that was false was either p_2~or~p_3. So one of them being false makes all of them be false.

So, the three propositions always have the same truth value, and so they're all equivalent.

5 0
3 years ago
Evaluate h -2 g for h = 3 and g = 27.
quester [9]
Evaluate h -2 g for h = 3 and g = 27.plug in both values...
3-2(27)
3-54
Answer:
51

3 0
3 years ago
How many terms are in this expression 9a + 6b + 3c + 1
satela [25.4K]

Answer:

3

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
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