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Shkiper50 [21]
3 years ago
15

Describe the continuity correction (covered in an earlier course unit), and explain how, when, and why it is used in statistics.

Don't limit your thinking to the most common example given of this corrective step: approximation of binomials using the Normal distribution. While that is an example of such a correction, it is only one example. (Hint: You could compare the development of this correction logic for discrete distributions to the use of integration against continuous distributions.) Discuss the more general case and how it affects probabilities you might need to calculate as an engineering working on a project.
Mathematics
1 answer:
garri49 [273]3 years ago
8 0

Answer:

Step-by-step explanation:

In probability theory, a continuity correction is an adjustment that is made when a discrete distribution is approximated by a continuous distribution.

For example, when you want to approximate a binomial with a normal distribution. According to the Central Limit Theorem, the sample mean of a distribution becomes approximately normal if the sample sizeis large enough. The binomial distribution can be approximated with a normal distribution too, as long as n*p and n*q are both greater than equal to 5.

The continuity correction factor a way to account for the fact that a normal distribution is continuous, and a binomial is not. When you use a normal distribution to approximate a binomial distribution, you’re going to have to use a continuity correction factor. It’s as simple as adding or subtracting 0.5 to the discrete x-value: use the following table to decide whether to add or subtract.

If   P(X=n) use   P(n – 0.5 < X < n + 0.5)

If   P(X>n) use   P(X > n + 0.5)

If   P(X?n) use P(X < n + 0.5)

If P (X<n) use   P(X < n – 0.5)

If P(X ? n) use   P(X > n – 0.5)

Example:

If P(X?351), use P (X?351-0.5)= P (X?350.5)

On the other hand, when the normal approximation is used to approximate a discrete distribution, a continuity correction can be employed so that we can approximate the probability of a specific value of the discrete distribution.

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James starts off with a hundred dollars and loses 6 dollars a week. Lara starts off with 160 dollars and loses 10 a week. At what week will they both have the same amount of money?
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jolli1 [7]

Answer:

Ratio of Ed's share :  Dave's share  = 4 : 5

Step-by-step explanation:

Total amount shared =  £720

Let us assume that Dave receives =  £m

So, Chris's share = £90 + m

Also, Chris's share : Dave's Share = 7: 5

⇒\frac{90 + m}{m}  = \frac{7}{5}

Here, solving for m , we get :  5(90 + m) = 7m

or,  450 + 5m = 7m

⇒ 2m = 450, ⇒ m = 225

So, Dave's Share =  m = £225

Chris's share = £90 + m = 225 + 90  = £ 315

Hence, Ed's share = Total - ( sum of Dave's and Chris's share)

= 720 -( 315 + 225) = £180

So, ratio of Ed's share :  Dave's share = £180 : £225

or, Ratio of Ed's share :  Dave's share  = 4: 5

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In circle K shown, the measure of NPL is twice the measure of NL . Which of the following is the measure
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Please consider the complete question.

Let x represent measure of arc NL.

We have been given that measure of arc NPL is twice the measure of arc NL. So measure of arc NPL would be 2x.

We know that measure of all arcs in a circle is equal to 360 degrees, so we can set an equation as:

\widehat{NL}+\widehat{NPL}=360^{\circ}

Upon substituting measure of both arcs, we will get:

x+2x=360^{\circ}

3x=360^{\circ}

\frac{3x}{3}=\frac{360^{\circ}}{3}

x=120^{\circ}

The measure of arc NPL would be 2x\Rightarrow 2(120^{\circ})=240^{\circ}.

We can see that angle NML is inscribed angle of arc NPL. We know that measure of an inscribed angle is half the measure of intercepted arc.

m\angle NML=\frac{1}{2}m\widehat{NPL}

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m\angle NML=120^{\circ}

Therefore, the measure of angle NML is 120 degrees and 3rd option is the correct choice.

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