Answer:
The zeroes in this equation are -5, -4, and 5
Step-by-step explanation:
In order to find these, you need to factor by splitting. For this, we separate out the two halves of the equation and pull out the greatest common factor of each. Let's start with the front end.
r^3 + 4r^2
r^2(r + 4)
Now the second half.
-25r - 100
-25(r + 4)
Since what is left in the parenthesis are exactly the same, we can use that parenthesis next to one with what we pulled out.
(r^2 - 25)(r + 4)
And we can further factor the first parenthesis using the difference of two squares
(r^2 - 25)(r + 4)
(r + 5)(r - 5)(r + 4)
Now that we are fully factored, set each parenthesis equal to 0 and solve for x.
r + 5 = 0
r = -5
r - 5 = 0
r = 5
r + 4 = 0
r = -4
Tbh I would say ounces or grams. I wouldn't make a final decision on my answer though.
._.
Answer:
y = 4/5
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
7/8y + 1/2 = 1 1/5
<u>Step 2: Solve for </u><em><u>y</u></em>
- Convert to improper fraction: 7/8y + 1/2 = 6/5
- [Subtraction Property of Equality] Subtract 1/2 on both sides: 7/8y = 7/10
- [Division Property of Equality] Divide 7/8 on both sides: y = 4/5
So basically what you have to do is first identify all of the sides or angles that equal eachother then you can see if you did a side side and side in a row etc, like 44 would be SAS because the vertical angles would be inbetween the two sides. 46 would be SSS because after you make the line in the middle for reflexive property you can see that there are three sides in a row. If this didnt help i recommend looking on Khan Academy
Divid the differince of the x's by 2 and the diffence of the y's also by 2
8/2,4/2 is (4,2)
M=(4,2)
hope this helps
:)
