The answer is 7. If you follow the order of PEMDAS this is an easy question.
Answer:
he grows by 5 cm every year between 1999 and 2006
Step-by-step explanation:
This is a arithmetic progression problem with the formula;
T_n = a + (n - 1)d
We are told that In 1999 Daniel was 146 cm tall. He grew to be 176 cm by the year 2006.
Thus;
a = 146
d = 2006 - 1999 = 7
Thus;
176 = 146 + (7 - 1)d
176 - 146 = 6d
30 = 6d
d = 30/6
d = 5 cm
Thus, he grows by 5 cm every year between 1999 and 2006
Answer:
and 
Step-by-step explanation:
A simple way to solve this problem is to plug the corresponding x and y into the function. We need only one pair since all the functions are quasi-linear (y=kx) and the increase is proportional.
In when x=3, y=15/4≈2.14
In 
when x=3, y=1.8
In when x=3, y≈2.33
In 
when x=3, y≈1.90
We can observe that in two cases, and , y is greater than 2.
Explanation:
The formula for calculating the percent change in a value between two points in time is:
p
=
N
−
O
O
⋅
100
Where:
p
is the percent change - what we are solving for in this problem.
N
is the New Value - 62 inches in this problem.
O
is the Old Value - 56 inches in this problem.
Substituting and solving for
p
gives:
p
=
62
−
56
56
⋅
100
p
=
6
56
⋅
100
p
=
600
56
p
=
10.7
rounded to the nearest tenth.
Ricardo gres 10.7%
Answer:
what im confused any body else ?
Step-by-step explanation:
