This stage is known as fetching.
- Any operation you do in a computer, it runs a lot of codes inside it, and these codes are in binary.
- For the operation, the computer accesses the RAM memory to gather information about this process, and moves it to the CPU, in a process named as fetching.
- Thus, the stage asked in this problem is known as fetching.
A similar problem is given at brainly.com/question/21536104
The answer to that would have to be c I think this is it so a feature bl bl bla
Answer:
Explanation:
#include <iostream>
using namespace std;
int costdays(int);
int costhrs(int,int);
int main()
{
int dd,hh,mm,tmph,tmpd,tmpm=0;
int pcost,mcost=0;
cout<<"Enter Parking time" << endl;
cout<<"Hours: ";
cin>>hh;
cout<<"Minutes: ";
cin>>mm;
if (mm>60)
{
tmph=mm/60;
hh+=tmph;
mm-=(tmph*60);
}
if (hh>24)
{
tmpd=hh/24;
dd+=tmpd;
hh-=(tmpd*24);
}
if ((hh>4)&&(mm>0))
{
pcost+=costdays(1);
}
else
{
mcost=costhrs(hh,mm);
}
cout<<"Total time: ";
if (dd>0)
{
cout<<dd<<"days ";
pcost+=costdays(dd);
}
pcost+=mcost;
cout<<hh<<"h "<<mm<<"mins"<<endl;
cout<<"Total Cost :"<<pcost<<"Won";
return 0;
}
int costdays(int dd)
{
return(dd*25000);
}
int costhrs(int hh,int mm)
{
int tmpm, tmp=0;
tmp=(hh*6)*1000;
tmp+=(mm/10)*1000;
tmpm=mm-((mm/10)*10);
if (tmpm>0)
{
tmp+=1000;
}
return(tmp);
}
Answer:
Since there are only two digits in binary, there are only two possible outcomes of each partial multiplication: If the digit in B is 0, the partial product is also 0. If the digit in B is 1, the partial product is equal to A.
Explanation:
Answer:
A varying infrastructure.
Explanation:
The competitive pressure it creates for multinational companies in the industry is one of difference in infrastructure because different technical standards are found in different parts of the world.
For instance, A technical standard known as Global Systems for Mobile (GSM) is common in Europe, and an alternative standard, Code Division Multiple Access (CDMA), is more common in the United States and parts of Asia.
Consequently, equipment designed for GSM will not work on a CDMA network and vice versa as a result of varying infrastructure, so companies would be innovative in order to improve on their products.