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2 years ago

What times what equals -152 and when added equals 12

Mathematics

1 answer:

sergeinik [125]2 years ago

6 0

You can set up an equation to figure this out.

-152+x=12

Add 152 to both sides and you get:

x=164

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HELP! please! ASAP! pleasee

murzikaleks [220]

Answer:

11.9

Step-by-step explanation:

I just know this off the top of my head

The real one is 11.18034

3 0

2 years ago

Simplify the following expression:<br><br> (66)4

iren [92.7K]

Step-by-step explanation:

Given

$( {6}^{6})^{4} \\ = {6}^{6 \times 4} \\ = {6}^{24} \\ = 4.7383813e18$

3 0

3 years ago

Jan uses 6 grams of tea leaves to make 24 fluid ounces of tea. Last week she made 288 fluid ounces of tea. How many grams of tea

Reil [10]

Hello!

288 / 24 = 12

6 * 12 = 72

Jan used 72 grams of tea leaves to make tea.

4 0

3 years ago

A local hamburger shop sold a combined total of 685 hamburgers and cheeseburgers on Wednesday. There were 65 fewer cheeseburgers

noname [10]

Answer:

620

Step-by-step explanation:

I might be wrong.

But based on the question both burgers are sold on a Wednesday so the question is asking how many cheeseburgers were sold on a Wednesday (which is the same day they both were sold) so I think you subtract.

so 685-65.

8 0

2 years ago

The population of a town grows at a rate proportional to the population present at time t. The initial population of 500 increas

Mazyrski [523]

Answer:

The population in 40 years will be 1220.

Step-by-step explanation:

The population of a town grows at a rate proportional to the population present at time t.

This means that:

$P(t) = P(0)e^{rt}$

In which P(t) is the population after t years, P(0) is the initial population and r is the growth rate.

The initial population of 500 increases by 25% in 10 years.

This means that $P(0) = 500, P(10) = 1.25*500 = 625$

We apply this to the equation and find t.

$P(t) = P(0)e^{rt}$

$625 = 500e^{10r}$

$e^{10r} = \frac{625}{500}$

$e^{10r} = 1.25$

Applying ln to both sides

$\ln{e^{10r}} = \ln{1.25}$

$10r = \ln{1.25}$

$r = \frac{\ln{1.25}}{10}$

$r = 0.0223$

$P(t) = 500e^{0.0223t}$

What will be the population in 40 years

This is P(40).

$P(t) = 500e^{0.0223t}$

$P(40) = 500e^{0.0223*40} = 1220$

The population in 40 years will be 1220.

7 0

3 years ago