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3 years ago

If f(x) = 3x - 1 and g(x) = x + 2, find ( f - g) (x) ?

Mathematics

1 answer:

mylen [45]3 years ago

8 0

(3x-1) - (x+2) = 2x -3

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. Which of the following is equivalent to 7 - 2(x + 2) < -4 - 3(1 - x)?

andre [41]

Step-by-step explanation:

$7 - 2(x + 2) < -4 - 3(1 - x)$

First, let's distribute the terms outside each parentheses to get rid of them:

$7 - 2x - 4 < -4 - 3 + 3x$

$-2x + 3 < -7 + 3x$

Next, let's move the terms with an $x$ variable to the left side of the equation, and everything else to the right side:

$-2x -3x < -7 - 3$

$-5x < -10$

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4 years ago

Given that Cheryl is collecting data on car color, what type of data is she working with?

Airida [17]

A. Qualitative
Bc it includes colors

5 0

3 years ago

Help quick pleaseee.........

Fofino [41]

Answer:

a) 341

b) 7243

c) 11018

d) 33000

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3 years ago

Reduce the following fraction: -32abc/64a^2bc^2

mafiozo [28]

Answer:

$-\dfrac{1}{2ac}$

Step-by-step explanation:

Given:

$\dfrac{-32abc}{64a^2bc^2}$

Reduce this fraction.

Work with numbers and different letters separately:

1. Numbers:

$\dfrac{-32}{64}=-\dfrac{32}{32\cdot 2}=-\dfrac{1}{2}$

2. Letter a:

$\dfrac{a}{a^2}=\dfrac{a}{a\cdot a}=\dfrac{1}{a}$

3. Letter b:

$\dfrac{b}b}=1$

4. Letter c:

$\dfrac{c}{c^2}=\dfrac{c}{c\cdot c}=\dfrac{1}{c}$

Hence,

$\dfrac{-32abc}{64a^2bc^2}=-\dfrac{1}{2}\cdot \dfrac{1}{a}\cdot \dfrac{1}{c}=-\dfrac{1}{2ac}$

5 0

3 years ago

Read 2 more answers

Write 43% as a decimal.

Natalija [7]

Answer:

0.43

Step-by-step explanation:

It's easy if you think of 43% as a decimal if you base it off 100. For example lets write a fraction about it: $\frac{43}{100}$ . A decimal you can think of the same way. 0.43 is the same as saying 43% of 100 or 43/100.

7 0

4 years ago