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2 years ago

How does the definition of the prefixes mono-,bi-, and tri- help when naming polynomials

Mathematics

2 answers:

Leviafan [203]2 years ago

8 0

Answer:

They let you know the number of numbers there are/will be.

Step-by-step explanation:

Mono, being one, means there will only be one number is the equation.

Bi, being two, means there will be two numbers in the equation.

and tri, being three, means there are three numbers in the equation.

Slav-nsk [51]2 years ago

6 0

Answer:

helps in figuring out how many terms a polynomial would have .

Step-by-step explanation:

Mono means one , we have a kind of polynomial known as monomial which means a polynomial would have one term . ex : x

bi means two . (binomial) which means the polynomial would have two terms . ex : x^3 + x^2

tri means two . we have a kind of polynomial called trionomial . which indicated that the polynomial would have two terms . ex : x^3+x^2+4

Bonus informations

polynomials are nothing but a variable based dialect in the language of math .
Polynomials are a string of variabless and numbers put together .
A constant polynomial is nothing but a monomial with degree 0 .

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trasher [3.6K]

Answer-

The estimated population in 2013 is 3081.

Solution-

This can be represented as exponential decreasing function,

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2 years ago

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2 years ago

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2 years ago

Calculating cos-1 ( help is gladly appreciated :) )

Alekssandra [29.7K]

Answer:

$\frac{3\pi}{4}$

(Assuming you want your answer in radians)

If you want the answer in degrees just multiply your answer in radians by $\frac{180^\circ}{\pi}$ giving you:

$\frac{3\pi}{4} \cdot \frac{180^\circ}{\pi}=\frac{3(180)}{4}=135^{\circ}$ .

We can do this since $\pi \text{ rad }=180^\circ$ (half the circumference of the unit circle is equivalent to 180 degree rotation).

Step-by-step explanation:

$\cos^{-1}(x)$ is going to output an angle measurement in $[0,\pi]$ .

So we are looking to solve the following equation in that interval:

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This happens in the second quadrant on the given interval.

The solution to the equation is $\frac{3\pi}{4}$ .

So we are saying that $\cos(\frac{3\pi}{4})=\frac{-\sqrt{2}}{2}$ implies $\cos^{-1}(\frac{-\sqrt{2}}{2})=\frac{3\pi}{4}$ since $\frac{3\pi}{4} \in [0,\pi]$ .

Answer is $\frac{3\pi}{4}$ .

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2 years ago