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Ratling [72]
4 years ago
10

Identify the independent variable in this relationship.

Mathematics
1 answer:
Kruka [31]4 years ago
6 0
Because changing m changes the amount of water it produces, m is the independent variable (g is dependent on the value of m).
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State weather your function is bounded above, bounded below or bounded.
ivolga24 [154]

Answer:

C is the answer

Step-by-step explanation:

6 0
3 years ago
A committee of three students met with the principal today and agreed that Rachel will report to the principal every $9$ days, J
Tom [10]

Answer:

180 days

Step-by-step explanation:

To solve for the least number of days all three will again be report to the principal, find the lowest common multiples of all three of them

Rachel will report to the principal every 9 days, Jessica every 12 days, and Richard every 15 days

Rachel (every 9 days) = 9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99, 108, 117, 126, 135, 144, 153, 162, 171, 180

Jessica (every 12 days) = 12, 24, 36, 48, 60, 72, 84, 96, 108, 120, 132, 144, 156, 168, 180

Richard (every 15 days) = 15, 30, 45, 60, 75, 90, 105, 120, 135, 150, 165, 180

The lowest common multiples of 9 days, 12 days, 15 days is 180 days

Therefore, the least number of days all three will report again to the principal is 180 days

4 0
3 years ago
marie purchasing memo paper for the office. the supplier offers 8 packs for $2.16 or 18 packs for $4.99. which is the better buy
Maurinko [17]

The better buy is 18 packs for $4.99.

8 0
3 years ago
61 random samples of city rent prices are selected from a normally distributed population the samples have a mean of $738 and a
Alenkinab [10]

Answer:

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Step-by-step explanation:

You need the Z value which for 95% confidence interval is 1.96. The mean is $738 and the standard deviation of $41.

X-Zs/\sqrt{n} \\ X+Zs/\sqrt{n}

Therefore we can calculated the confidence interval

738-1.96\cdot{41}/\sqrt{61} =738-10.3

738±10.3

The interval is (728,748)

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How do u find the rule of a table of coordinates for cartesian planes
otez555 [7]

Answer:

Measure it or something

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