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3 years ago

Describe how to convert from vertex form to standard form.

Mathematics

2 answers:

tino4ka555 [31]3 years ago

7 0

Answer:

To convert the vertex form back to standard form, simply square the binomial, distribute a, and add the constants. y=3(x+1)^2+5 y=3(x^2+2x+1)+5 y=3x^2+6x+3+5 y=3x^2+6x+8 This is the original standard form of the equation.

Step-by-step explanation:

Elenna [48]3 years ago

5 0

Answer:

So basically in that example you are just going to square the x-1 because of pemdas, then multiply by 3, then add 2.

Step-by-step explanation:

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Answer:

The first one is equivalent [the 6x+48 = 2(3x+24)] and the second one is NOT equivalent [the 7x+21 ≠ 2(5x+3)]

Step-by-step explanation:

Just follow distributive property to solve these. You can ignore the first expression in both until you have to compare the answers.

1. 6x+48 and 2(3x+24)

2(3x+24) ---> 2(3x) + 2(24) ---> 6x + 48

Bring in the first expression ~ 6x+48 and 6x+48

They are the same, so they are equivalent

2. 7x+21 and 2(5x+3)

2(5x+3) ---> 2(5x) + 2(3) ----> 10x + 6

Bring in the first expression ~ 7x+21 and 10x + 6

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