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Jet001 [13]
3 years ago
6

What are secondary reference electrodes.

Chemistry
1 answer:
Misha Larkins [42]3 years ago
8 0

Answer: Is an electrode which has a stable and well-known electrode potential.

Explanation:

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Name the following ionic compounds: (a) K2Cr2O7, (b) Li2C2O4, (c) CuNO3.
Elis [28]

Answer :

(a) The name of K_2Cr_2O_7 is, potassium dichromate.

(b) The name of Li_2C_2O_4 is, lithium oxalate.

(c) The name of CuNO_3 is, copper nitrate.

Explanation:

Ionic compound : It is a type of compound that is made up of the ions of the two different elements in which one element is a metal and another element is a non-metal.

(a) K_2Cr_2O_7

The given compound K_2Cr_2O_7 is an ionic compound. It is made up of two different ions which are potassium ion (K^+) and dichromate ion (Cr_2O_7^{2-}).

So, the name of K_2Cr_2O_7 is, potassium dichromate.

(b) Li_2C_2O_4

The given compound Li_2C_2O_4 is an ionic compound. It is made up of two different ions which are lithium ion (Li^+) and oxalate ion (C_2O_4^{2-}).

So, the name of Li_2C_2O_4 is, lithium oxalate.

(c) CuNO_3

The given compound CuNO_3 is an ionic compound. It is made up of two different ions which are copper ion (Cu^+) and nitrate ion (NO_3^{-}).

So, the name of CuNO_3 is, copper nitrate.

4 0
3 years ago
What gas on earth acts like a metal in the atmosphere of Jupiter?
lord [1]
The answer to your question is liquid hydrogen

8 0
4 years ago
What color does red cabbage juice make when mixed with a citrus cleaner?
Nina [5.8K]

Answer: PINK

Explanation:

7 0
2 years ago
Read 2 more answers
Iodine-131 half life 8.040 how long will it take for a 40 gram sample of iodine-131 to decay to 0.75 grams
otez555 [7]

Answer:

See explanation below

Explanation:

To get this, we need to apply the general expression for half life decay:

N = N₀e(-λt)    (1)

Where:

N and N₀ would be the final and innitial quantities, in this case, masses.

t: time required to decay

λ: factor related to half life

From the above expression we need λ and t. To get λ we use the following expression:

λ = t₁₂/ln2   (2)

And we have the value of half life, so, replacing we have:

λ = 8.04 / ln2 = 11.6

Now, we can replace in (1) and then, solve for t:

0.75 = 40 exp(-11.6t)

0.75 / 40 = exp(-11.6t)

ln(0.01875) = -11.6t

-3.9766 = -11.6t

t = -3.9766 / -11.6

<h2>t = 0.34 days</h2><h2></h2>
3 0
3 years ago
Glucose, C6H12O6, is a good source of food energy. When it reacts with oxygen, carbon dioxide and water are formed. How many lit
Arte-miy333 [17]

Answer:b

Explanation:

From the question, the stoichiometry of the balanced reaction equation showed that 180gof glucose give 134.4L of CO2. Then we are given to find the volume of carbon IV oxide given off by 126g of glucose. This is done as shown in the image by relating what is given to the stoichiometry of the balanced reaction equation to obtain the answer as shown.

6 0
3 years ago
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