A magnet moved near a coil of wire can cause a(n)
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Answer:
The amount of precipitate formed would 7.175 grams of silver chloride.
Explanation:
Moles of NaCl = n
Volume of NaCl solution = 50.0 mL = 0.050 L
Molarity of the hydrogen peroxide = 2.0 M
Moles of silver nitarte = n'
Volume of silver nitrate solution = 50.0 mL = 0.050 L
Molarity of the silver nitrate = 1.0 M
According to reaction, 1 mole of of silver nitrate reacts with 1 mole of NaCl. Then 0.050 mole of silve nitrate will :
of NaCl
This means that silver nitrate is in limiting amount and NaCl is in excessive amount.
So, the amount of AgCl depends upon amount of silver nitrate.
According to reaction, 1 mole of silver nitrate gives 1 mole of AgCl.
Then 0.050 moles of silver nitrate will give;
of AgCl
Mass of 0.050 moles of AgCl ;
The amount of precipitate formed would 7.175 grams of silver chloride.
Answer:
The IUPAC name of compound is 6-Ethyl-2-Octene.
Explanation:
First of all draw a straight chain of 8 carbon atoms.
Make a double bond between carbon number 6 and 7 numbering from left.
Add ethyl group at position 3 starting from left.
The structure sketched is attached below,
According to rules the longest chain containing a double bond is selected. Numbering is started from the end to which double bond is nearer. So, in our case the double bond starts at carbon 2, hence parent name of compound is 2-Octene. Then the substituent at position 6 is named.
The IUPAC name of compound is 6-Ethyl-2-Octene.
Explanation:
First of all draw a straight chain of 8 carbon atoms.
Make a double bond between carbon number 6 and 7 numbering from left.
Add ethyl group at position 3 starting from left.
The structure sketched is attached below,
According to rules the longest chain containing a double bond is selected. Numbering is started from the end to which double bond is nearer. So, in our case the double bond starts at carbon 2, hence parent name of compound is 2-Octene. Then the substituent at position 6 is named.