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Alina [70]
3 years ago
11

Please help! What is the coefficient of the term of degree 4 in the polynomial below?

Mathematics
1 answer:
snow_tiger [21]3 years ago
6 0

Answer:

3

Step-by-step explanation:

term of degree 4 is the term with the exponent of 4

3x^4 is the term of degree 4 so the coefficient is 3

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Mrs Perry shares out 21 biscuits between
avanturin [10]

Answer:

Gemma gets 3 biscuits

Zak gets 18 biscuits

Step-by-step explanation:

1:6 = 1+6

= 7

1/7 * 21 = 3

6/7 * 21 = 18

4 0
3 years ago
Read 2 more answers
What is the next fraction in this sequence? Simplify your answer. 3/4, 1/4, 1/12, 1/36
antiseptic1488 [7]
Hey their,

3/4 
1/4
1/12
1/36
0/60

The pattern is -1/x every 2 +x/8 

How i got this was 36/12=3
3*12=36
so 60-36=24
24x3/2+24=60
then 60/5=12

Hopethis helped


7 0
3 years ago
PLZ ANSWER! ILL GIVE YOU BRAINIEST IF YOU ANSWER IN 2
V125BC [204]

Answer:

-4;-4

Step-by-step explanation:

these would be the coords because each of the lines represents 2 units

6 0
2 years ago
mia hired a moving company, it charged 500$ for service mia give them a 16% tip.How much did she tip the movers,
snow_tiger [21]

Answer: 80 dollars

Step-by-step explanation:

You can find a percentage with one of two ways.

For hundreds like this, oftentimes it's quicker and more simple to think of it as just 100. The proportion from 100 to 500 is just 5.  16% of 100 is 16. So, multiply 16 * 5. You would get 80.

The second method is you can use 0.16 * 500. It's the more conventional method, and you get 80, like the last method.

3 0
3 years ago
A particle moves along the curve y = 5x^2 – 1 in such a way that the y value is decreasing at the rate of 2 units per second. At
Shtirlitz [24]

Answer:

The correct option is;

Increasing one fifth unit/sec

Step-by-step explanation:

The equation that gives the curve of the particle of the particle is y = 5·x² - 1

The rate of decrease of the y value dy/dt = 2 units per second

We have;

dy/dx = dy/dt × dt/dx

dy/dx = 10·x

dy/dt = 2 units/sec

dt/dx = (dy/dx)/(dy/dt)

dx/dt = dy/dt/(dy/dx) = 2 unit/sec/(10·x)

When x = 1

dx/dt = 2/(10·x) = 2 unit/sec/(10 × 1) = 1/5 unit/sec

dx/dt = 1/5 unit/sec

Therefore, x is increasing one fifth unit/sec.

8 0
3 years ago
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