Answer:
Bottom left
Step-by-step explanation:
For it to be scalene, all 3 sides must be of different length, so cross off D. Acute means all angles are less then 90°, so cross off the top 2.
Answer:
Option A.)−4
Step-by-step explanation:
we have
4x+5y=-12 -----> equation A
-2x+3y=-16 -----> equation B
Solve the system of equations by elimination
Multiply the equation B by 2
2*(-2x+3y)=-16*2
-4x+6y=-32 -----> equation C
Adds equation A and equation C
4x+5y=-12
-4x+6y=-32
-----------------
5y+6y=-12-32
11y=-44
y=-4
The value of that <span>(√5 + 1)/8 and We can prove it like this:
</span>cos 2A= 2cos^2 A-1=1-2sin^2 A
<span>so cos^2 48 – sin^2 12 </span>
<span>=(1/2)(1+cos 96) - (1/2)(1-cos24) </span>
<span>=(1/2)(cos 96 +cos 24) and using cos(A)+cosB)=2cos((A+B)/2)cos((A-B)/2) </span>
<span>=cos60cos36 </span>
<span>=(1/2)cos36 </span>
<span>and you have to find cos36. </span>
<span>Suppose 5x=180, then </span>
<span>cos(5x)=cos(180) then x=-180,-108, -36, 36, 108 </span>
<span>Also 3x=180-2x </span>
<span>so cos(3x)=cos(180-2x)=-cos2x </span>
<span>so 4cos^3(x) -3cos(x)=1 - 2cos^2(x) </span>
<span>giving 4c^3+2c^2 - 3c-1=0 where c=cosx </span>
<span>c=-1 is a root and factorizing gives </span>
<span>(c+1)(4c^2-2c-1)=0 </span>
<span>so 4c^-2c-1=0 giving </span>
<span>c=(2±√20)/8=(1±√5)/4 and these have values cos(36) and cos(108) </span>
<span>the positive root is therefore cos(36)=(1+√5)/4 </span>
<span>and the required value (1/2)cos(36)=(1+√5)/8
</span>I think this can be very useful
