Answer:
The area of triangle K is 16 times greater than the area of triangle J
Step-by-step explanation:
we know that
If Triangle K is a scaled version of Triangle J
then
Triangle K and Triangle J are similar
If two triangles are similar, then the ratio of its areas is equal to the scale factor squared
Let
z -----> the scale factor
Ak ------> the area of triangle K
Aj -----> the area of triangle J
so

we have

substitute



therefore
The area of triangle K is 16 times greater than the area of triangle J
The answer is no, the side lengths are not persevered. <span />
I'm confused when I did it I got .35 and you divide
hope it helped
1. -16, -9, -3, 0, 5, 8, 25
2. 26, 13, 7, 6, 2, -1, -3, -50
Espero que esto ayude!