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pogonyaev
3 years ago
9

What is the value of the 23rd term in the sequence 10, 8, 6, 4, ...

Mathematics
2 answers:
Alchen [17]3 years ago
7 0
<span>This is an arithemetic sequence of form: a(n) = a + (n-1)d, where a = first term (10), n is the term in question (23) and d = difference in terms (-2) Notice the ...</span><span>
</span>
lubasha [3.4K]3 years ago
5 0
I think the 23rd term would be -34...
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Will give brainliestt
Natasha_Volkova [10]

Answer: (-5, -3)

Step-by-step explanation:

(-10, -6)

-10/2 = -5

-6/2 = -3

7 0
3 years ago
In the expansion (ax+by)^7, the coefficients of the first two terms are 128 and -224, respectively. Find the values of a and b
madam [21]

Answer:

a = 2, b = 3.5

Step-by-step explanation:

Expanding (ax+by)^7 using Binomial expansion, we have that:

(ax+by)^7 =

(ax)^7(by)^0 + (ax)^6(by)^1 + (ax)^5(by)^2 + (ax)^4(by)^3 + (ax)^3(by)^4 + (ax)^2(by)^5 + (ax)^1(by)^6 + (ax)^0(by)^7

= (a)^7(x)^7+ (a)^6(x)^6(b)(y) + (a)^5(x)^5(b)^2(y)^2 + (a)^4(x)^4(b)^3(y)^3 + (a)^3(x)^3(b)^4(y)^4 + (a)^2(x)^2(b)^5(y)^5 + (a)(x)(b)^6(y)^6 + (b)^7(y)^7\\\\\\= (a)^7(x)^7+ (a)^6(b)(x)^6(y) + (a)^5(b)^2(x)^5(y)^2 + (a)^4(b)^3(x)^4(y)^3 + (a)^3(b)^4(x)^3(y)^4 + (a)^2(b)^5(x)^2(y)^5 + (a)(b)^6(x)(y)^6 + (b)^7(y)^7

We have that the coefficients of the first two terms are 128 and -224.

For the first term:

=> a^7 = 128

=> a = \sqrt[7]{128}\\ \\\\a = 2

For the second term:

a^6b = -224

b = \frac{-224}{a^6}

b = \frac{-224}{2^6} \\\\\\b = \frac{-224}{64} \\\\\\b = 3.5

Therefore, a = 2, b = 3.5

5 0
3 years ago
Jose works out at a gym. He rides a stationary bike for a certain amount of minutes and walks on a treadmill for a certain amoun
Naya [18.7K]
Well after reading this 100 times I haven't found a 100% sure answer but I think its A



hope its right and it helps :D
5 0
3 years ago
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If the flare is launched with an initial velocity of 144 feet per second, find the height after 2 seconds. The answer is not 288
Rashid [163]
H= ut -16 t^2

h = 144(2) - 16 (4)

= 288 - 64 = 224
4 0
3 years ago
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