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DerKrebs [107]
3 years ago
15

Please help me ASAP

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
7 0
Umm what is this……lol
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Mathematical x4 - x2 ≥ 2x
kondaur [170]
X4-x2≥ 2x~~~2x≥ 2x True Because " _ " is the same thing with "=" ; and because 2x=2x then 2x≥ 2x ~~~~~~Have a nice day!!! ★★
4 0
3 years ago
Find an equation of the line that satisfies the given conditions. through (9, 7); perpendicular to the line y = 5
cluponka [151]
The answer would defintley be 69 if you want the right answer.
5 0
3 years ago
Find the general solution of the following ODE: y' + 1/t y = 3 cos(2t), t > 0.
Margarita [4]

Answer:

y = 3sin2t/2 - 3cos2t/4t + C/t

Step-by-step explanation:

The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt

Comparing the standard form with the given differential equation.

p(t) = 1/t and q(t) = 3cos(2t)

I = e^∫1/tdt

I = e^ln(t)

I = t

The general solution for first a first order DE is expressed as;

y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.

yt = ∫t(3cos2t)dt

yt = 3∫t(cos2t)dt ...... 1

Integrating ∫t(cos2t)dt using integration by part.

Let u = t, dv = cos2tdt

du/dt = 1; du = dt

v = ∫(cos2t)dt

v = sin2t/2

∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt

= tsin2t/2 - cos2t/4 ..... 2

Substituting equation 2 into 1

yt = 3(tsin2t/2 - cos2t/4) + C

Divide through by t

y = 3sin2t/2 - 3cos2t/4t + C/t

Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t

3 0
3 years ago
Express in the form 1 : n Give n as a decimal 10 : 12
Studentka2010 [4]

Answer:

1:1.2

Step-by-step explanation:

please give me a brainliest!!<3

7 0
3 years ago
What is the answer to -12(1 3/4)<br> Someone please help
JulsSmile [24]
The answer should be -21
7 0
2 years ago
Read 2 more answers
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