Answer:
i would say false
Step-by-step explanation:
Let (x,y) be an arbitrary point on the circle.
Then d = √[x-3)2 + (y-0)2] = √[x2 - 6x + 9 + y2]
Since x2 + y2 = 1, y2 = 1-x2.
So, d = √[x2 - 6x + 9 + 1 - x2]
d = √(-6x+10)
Domain: x is the x-coordinate of a point on the circle centered at (0,0) with radius 1. So, -1≤x≤1.
But, for d to be defined, we need -6x+10 ≥ 0. So, x ≤ 5/3 (True for all x in [-1,1]).
Domain = [-1,1]
Range: -1 ≤ x ≤ 1 So, 6 ≥ -6x ≥ -6
16 ≥ -6x+10 ≥ 4
4 ≥ √(-6x+10) ≥ 2 That is, 2 ≤ d ≤4
Range: [2,4]
Step-by-step explanation:
Answer:
Mode:7
Median:2
Mean:5.2
Range:7
Step-by-step explanation:
see the picture attached
Answer:
-<u> 55 </u> = -6.88
8
Step-by-step explanation:
5 X 5 / 8 - 10
<u> 5² </u> - 10
8
<u> 25 - 80 </u>
8
-<u> 55 </u> = -6.88
8
