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3 years ago

Help please!! Show work if possible!

Mathematics

1 answer:

Natasha2012 [34]3 years ago

5 0

Answer:

Please see the attached pictures for full solution.

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What is the KE of a 1 kg ball traveling at 20 meters per second?

Sonbull [250]

The easiest way to find that answer is to look at the solution that I just gave you for the same ball traveling at 30 M/Sec, and just substitute 20 in place of 30 in that solution.

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3 years ago

Convert 2.3 radians to degree measure

zmey [24]

Answer:131.78

Step-by-step explanation:

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4 years ago

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PLZZZ HELPPP!!!!!!!!!!

miv72 [106K]

Hello!

$\large\boxed{2x + y = 3}$

Begin by finding the slope that would be perpendicular to the given equation.

A perpendicular line has a slope that is the opposite reciprocal of the original. Therefore:

1/2 --> -2

Find the answer choice that contains a slope of -2 when rewritten in the form y = mx + b:

Choice 1:

x + 2y = 2

Move x to the other side:

2y = -x + 2

Divide both sides by 2:

y = -1/2x + 1. This choice is incorrect.

Choice 2:

x - 2y = -12

Move x to the other side:

-2y = -x - 12

Divide both sides by -2:

y = 1/2x + 6. This choice is incorrect.

Choice 3:

2x + y = 3

Move 2x to the other side:

y = -2x + 3. This contains a slope of -2, which is correct.

Choice 4:

y - 2x = -5

Move -2x to the opposite side:

y = 2x - 5. This contains a slope of positive 2, so it is incorrect.

The correct answer is 2x + y = 3.

7 0

3 years ago

Read 2 more answers

A quadrilateral has vertices at A(–5, 5), B(1, 8), C(4, 2), D(–2, –2). Use slope to determine if the quadrilateral is a rectangl

lianna [129]

With the properties of rectangle in mind we must perform two verification. Verify to see if opposite sides are parallel and adjacent sides are perpendicular.

We need to determine the slope of each side, using the formula,

$m=\frac{y_2-y_1}{x_2-x_1 }$

Slope of AB

$m_{AB}=\frac{8-5}{1--5}$

$\Rightarrow m_{AB}=\frac{8-5}{1+5}$

$\Rightarrow m_{AB}=\frac{3}{6}$

$\Rightarrow m_{AB}=\frac{1}{2}$

Slope of BC

$m_{BC}=\frac{2-8}{4-1}$

$\Rightarrow m_{BC}=\frac{-6}{3}$

$\Rightarrow m_{BC}=-2$

Slope of CD

$m_{CD}=\frac{-2-2}{-2-4}$

$\Rightarrow m_{CD}=\frac{-2-2}{-2-4}$

$\Rightarrow m_{CD}=\frac{-4}{-6}$

$\Rightarrow m_{CD}=\frac{2}{3}$

Slope of AD

$m_{AD}=\frac{-2-5}{-2--5}$

$\Rightarrow m_{AD}=\frac{-2-5}{-2+5}$

$\Rightarrow m_{AD}=\frac{-7}{3}$

Verify Parallel sides

If the quadrilateral is a rectangle, then opposite sides should have the same slope. But

$m_{AD} = \frac{-7}{3} \neq m_{BC}=-2$

$m_{AB}=\frac{1}{2} \neq m_{CD}=\frac{2}{3}$

Verify Perpendicularity

And also the product of slopes of all sides with a common vertex should be -1. But

$m_{AB} \times m_{BC}=\frac{1}{2} \times -2=-1$

$m_{AB} \times m_{AD}=\frac{1}{2} \times -\frac{7}{3} \neq -1$

$\Rightarrow m_{CD} \times m_{AD}=\frac{2}{3} \times -\frac{7}{3} \neq -1$

$\Rightarrow m_{CD} \times m_{BC}=\frac{2}{3} \times -2 \neq -1$

Since the quadrilateral fails to satisfy all these conditions, the quadrilateral is not a rectangle

6 0

3 years ago

If 120% of a is equal to 80% of b, then what is the value of a b in terms of b

SOVA2 [1]

If you would like to know what is the value of a b in terms of b, you can calculate this using the following steps:

120% of a = 80% of b
120/100 * a = 80/100 * b /*100
120 * a = 80 * b /120
a = 80 / 120 * b
a = 2/3 * b

The correct result would be a = 2/3 * b.

3 0

4 years ago

Read 2 more answers