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Strike441 [17]
3 years ago
14

- 4x - y = 24 Complete the missing value in the solution to the equation. .8)

Mathematics
1 answer:
Akimi4 [234]3 years ago
6 0

24+8=32.
32/-4= -8.
so (-8,8) or x=-8 and y=8
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6,859^1/3 can be written as
zloy xaker [14]

Answer:

∛6859   ( = 19).

Step-by-step explanation:

6,859^1/3 = ∛6859  (the cube root of 6859).

Using a calculator we see that this = 19.

4 0
3 years ago
What is the answer? Reduce 981/387
Sergeu [11.5K]
\frac{981}{387}\\\\981\to9+8+1=18-is\ divisible\ by\ 9\\\\387\to3+8+7=18-is\ divisible\ by\ 9\\\\\frac{981:9}{387:9}=\frac{109}{43}\\\\109\ and\ 43\ are\ the\ prime\ numbers\\\\Answer:\boxed{\frac{981}{387}=\frac{109}{43}=2\frac{23}{43}}
7 0
3 years ago
Read 2 more answers
If a = and b = -1 what is the value of ab -b^2
svet-max [94.6K]

Answer:

-2

Step-by-step explanation:

To solve you need to replace the variables with their numbers.

3(-1) - (-1^2)

-1 x -1 = -1

3 x (-1) = -3

-3 - (-1) =

-2

8 0
3 years ago
Find the volume of a cone with a radius of 8 cm and height 15 cm? Round to the nearest tenth. Please show work.
Nonamiya [84]
You multiply radius by 3.14 by the height  if you plug it in your equation is 8×3.14×15 which equals 1005.31 which rounds to 1005, the answer is 1005! :D
4 0
2 years ago
Suppose that a is a one-dimensional array of ints with a length of at least 2. Which of the following code fragments successfull
elixir [45]

Answer:

E)II and III only

Step-by-step explanation:

This can be seen with examples. Say a[0]=1 and and a[1]=2.

for I , the first line of code would be:

a[0]=a[1];

thus, we would get a new value for a[0]=2.

The second line of code

a[1]=a[0]; uses the new value of a[0], so we would get a[1]=2.

The end result is a[0]=2, and a[1]=2 which doesn't exchange the values of the first two elements.

For II the first line of code

int t= a[0]; saves the original value of a[0] to t, so we get t=1.

the second line of code

a[0]=a[1]; changes the value of a[0]  to that of a[1]. Thus, in our example a[0]=2.

the final line

a[1]=t; changes the value of a[1] to the original value of a[0], giving us a[1]=1 and a[0]=2, what we were looking for.

For III

the first line of code

a[0]=a[0]-a[1];

gives us

a[0]=1-2

the secon line

a[1]=a[1]+a[0];

takes the new value of a[0] and replaces it in the expression

a[1]= 2+(1-2)=1

the last line

a[0]=a[1]-a[0];

takes the new value of a[0] and a[1] and replaces the in the expression

a[0]=1-(1-2)=1-1+2=2

which exchanges the values needed.

So we can see that only II and III do what we require, giving us E as the answer.

6 0
3 years ago
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