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tekilochka [14]

3 years ago

9

A boy owns 2 pairs of pants, 1 shirts, 6 ties, and 1 jackets. How many different outfits can he wear to school if he must wear o

ne of each

1 answer:

liubo4ka [24]3 years ago

4 0

The boy have to wear 4 from one of each to school.

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school uniform cost $25 plus a one time $5 fee if you get your initials embroidered on the collar . how much did bryce pay if he

daser333 [38]

4 embroidered uniforms= $5 fee for each 4 embroidered uniform and $25 for each uniform. 5 x 4 = 20. 25 x 4 = 100. 100 + 20= 125. He paid $120 for the embroidered uniform.

5 0

3 years ago

Determine the number of possible solutions for a triangle with B=37 degrees, a=32, b=27

vladimir1956 [14]

Answer:

Two possible solutions

Step-by-step explanation:

we know that

Applying the law of sines

$\frac{a}{sin(A)}=\frac{b}{Sin(B)}=\frac{c}{Sin(C)}$

we have

$a=32\ units$

$b=27\ units$

$B=37\°$

step 1

Find the measure of angle A

$\frac{a}{sin(A)}=\frac{b}{Sin(B)}$

substitute the values

$\frac{32}{sin(A)}=\frac{27}{Sin(37\°)}$

$sin(A)=(32)Sin(37\°)/27=0.71326$

$A=arcsin(0.71326)=45.5\°$

The measure of angle A could have two measures

the first measure-------> $A=45.5\°$

the second measure -----> $A=180\°-45.5\°=134.5\°$

step 2

Find the first measure of angle C

Remember that the sum of the internal angles of a triangle must be equal to $180\°$

$A+B+C=180\°$

substitute the values

$A=45.5\°$

$B=37\°$

$45.5\°+37\°+C=180\°$

$C=180\°-(45.5\°+37\°)=97.5\°$

step 3

Find the first length of side c

$\frac{a}{sin(A)}=\frac{c}{Sin(C)}$

substitute the values

$\frac{32}{sin(37\°)}=\frac{c}{Sin(97.5\°)}$

$c=Sin(97.5\°)\frac{32}{sin(37\°)}=52.7\ units$

therefore

the measures for the first solution of the triangle are

$A=45.5\°$ , $a=32\ units$

$B=37\°$ , $b=27\ units$

$C=97.5\°$ , $b=52.7\ units$

step 4

Find the second measure of angle C with the second measure of angle A

Remember that the sum of the internal angles of a triangle must be equal to $180\°$

$A+B+C=180\°$

substitute the values

$A=134.5\°$

$B=37\°$

$134.5\°+37\°+C=180\°$

$C=180\°-(134.5\°+37\°)=8.5\°$

step 5

Find the second length of side c

$\frac{a}{sin(A)}=\frac{c}{Sin(C)}$

substitute the values

$\frac{32}{sin(37\°)}=\frac{c}{Sin(8.5\°)}$

$c=Sin(8.5\°)\frac{32}{sin(37\°)}=7.9\ units$

therefore

the measures for the second solution of the triangle are

$A=45.5\°$ , $a=32\ units$

$B=37\°$ , $b=27\ units$

$C=8.5\°$ , $b=7.9\ units$

6 0

3 years ago

How many 1/3 inch cubes does it take to fill a box with width 2 2/3 inches, lengths 3 1/3 inches, and height 2 1/3 inches?

Nataly [62]

Answer:

560 cubes

Step-by-step explanation:

width: 8 cubes

length: 10 cubes

height: 7 cubes

volume: 8*10*7=560

divided l, w, and h by 1/3 to get them in cubes

7 0

3 years ago

Read 2 more answers

Bonus solve the equation aݔ ଶ + 7x – 4 = 0 for x by using the quadratic formula.

victus00 [196]

   x² +   7x   - 4 = 0
a = 1, b = 7, c = -4

x = [-b +/- √(b² - 4ac)]/2a
   = [-7 +/- √(49 + 4)]/2
   = (-7 +/- √53)/2

3 0

3 years ago

How many unit cubes would you need to make a model of a rectangular prism that is 6 units long, 2 units wide, and 5 units high?

Zina [86]

Answer:

60

Step-by-step explanation:

Volume = 6*2*5 = 60

6 0

3 years ago

Read 2 more answers