Dividing decimals model

Mathematics

2 answers:

Zinaida [17]2 years ago

7 0

The answer is B;

8 x .1 = .8
And you have four groups of 8
.8 x 4 = 3.2

suter [353]2 years ago

4 0

The answer is B

hope this helps

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Which values of m and b will create a system of equations with no solution? Check all that apply. y = mx + b y = –2x + 3/2

Leni [432]

Lines with no solution are parallel lines....parallel lines will contain the same slope, but different y intercepts.

y = -2x + 3/2....slope (m) = -2 and y int (b) = 3/2
so the line we need will have a slope of -2, but can have any y int EXCEPT 3/2.

m = -2, and b = -1/3 is parallel, no solution
m = -2 and b = -2/3...parallel, no solution

7 0

3 years ago

Read 2 more answers

Help! How would I solve this trig identity?

NeTakaya

Using simpler trigonometric identities, the given identity was proven below.

<h3>How to solve the trigonometric identity?</h3>

Remember that:

$sec(x) = \frac{1}{cos(x)} \\\\tan(x) = \frac{sin(x)}{cos(x)}$

Then the identity can be rewritten as:

$sec^4(x) - sen^2(x) = tan^4(x) + tan^2(x)\\\\\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)} = \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)} \\\\$

Now we can multiply both sides by cos⁴(x) to get:

$\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)} = \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)} \\\\\\\\cos^4(x)*(\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)}) = cos^4(x)*( \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)})\\\\1 - cos^2(x) = sin^4(x) + cos^2(x)*sin^2(x)\\\\1 - cos^2(x) = sin^2(x)*sin^2(x) + cos^2(x)*sin^2(x)$