Answer:
(1) Area of second triangle= 50 cm^2.
(2) Area of ΔABC=98 cm^2.
and Area of ΔDFG=175 cm^2.
Step-by-step explanation:
<em>" For two similar triangles the ratio of sides is equal to the ratio of square of their areas".</em>
i.e. if a,b are the corresponding sides of two similar triangles and let A and B denote the area of two triangles then we have the relation as:

(1)
for the first question:
we have a=2, b=5.
A=8 cm^2.
Hence,

B=50 cm^2.
Hence, the area of second triangle is 50 cm^2.
(2)
In second option we have:
a=6 and b=5.
A-B=77 cm^2.
A=77+B

Hence area of second triangle i.e. ΔDFG is 175 cm^2.
and area of first triangle i.e. ΔABC=175-77=98 cm^2.
In order to form triangle PQT and quadrilateral TQRS, point T must lie on line PS which is 16 cm. long.
If the ratio of PT to TS is 5:3 and the total length of PS is 16, then PT must be 10 and TS must be 6 (10 + 6 =16) and 10:6 is the same ratio as 5:3. Another way to think about it is 5/3 = 10/6.
Now you have all the lengths that you need to find the areas of the quadrilateral and the triangle.
Make sure you draw a diagram of it!!
Answer:
Triangle - 21 units
Trapezoid - 65 units
Step-by-step explanation:
- Because this triangle and trapezoid are reflections of each other when split in half, remove the highlighted parts to make them a rectangle. When made into a rectangle, you can use the formula length * width to find the area of either shape (trapezoid or triangle).
- Note you won't be able to do this when solving for the area of ALL trapezoids and triangles.