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Law Incorporation [45]
3 years ago
12

The circumference of Fis 72 cm. What is the length of De (the minor arc)?

Mathematics
1 answer:
Marizza181 [45]3 years ago
3 0

Answer:C=2piR

R=18cm if you solve the equation

Step-by-step explanation:

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the bowling alley charges a flat rate of $50 for a birthday party plus $4.25 per person. If Emanuel only has $125 to spend. How
Maksim231197 [3]

125 > 50 + 4.25*p

subtract 50 from each side

75 =>4.25p

divide by 4.25

p>17.64

He may invite up to 17 people ( if he doesn't have to pay for himself)

He may invite 16 if he has to pay for himself

3 0
3 years ago
Is this a linear function? One person sends an email to 2 people. Those 2 people send it to 4 people, and those 4 send it to 8 p
Mumz [18]
Yes; this is a linear function because you plug in a number and multiply it by two, so the function would be y=2x, which is linear despite the fact that it lacks a b value.

Hope this helps! :)
8 0
4 years ago
One year after graduating from college, Sam earned $42,000. Each year, he earned $4000 more.
xxMikexx [17]
The answer is:
an=4000n+38,000

Sam has $42,000 one year after graduating. So when he graduates, he would have $38000.

Hope this helps!

4 0
4 years ago
Read 2 more answers
How would you describe the relationship between miles driven per week and car age, as shown in the scatterplot below? Choose eve
QveST [7]

Answer:

Negative and nonlinear

Step-by-step explanation:

hope this helped

5 0
3 years ago
(a) A lamp has two bulbs, each of a type with average lifetime 1400 hours. Assuming that we can model the probability of failure
Temka [501]

Answer:

For first lamp ; The resultant probability is 0.703

For both lamps; The resultant probability is 0.3614

Step-by-step explanation:

Let X be the lifetime hours of two bulbs

X∼exp(1/1400)

f(x)=1/1400e−1/1400x

P(X<x)=1−e−1/1400x

X∼exp⁡(1/1400)

f(x)=1/1400 e−1/1400x

P(X<x)=1−e−1/1400x

The probability that both of the lamp bulbs fail within 1700 hours is calculated below,

P(X≤1700)=1−e−1/1400×1700

=1−e−1.21=0.703

The resultant probability is 0.703

Let Y be a lifetime of another lamp two bulbs

Then the Z = X + Y will follow gamma distribution that is,

X+Y=Z∼gamma(2,1/1400)

2λZ∼

X+Y=Z∼gamma(2,1/1400)

2λZ∼χ2α2

The probability that both of the lamp bulbs fail within a total of 1700 hours is calculated below,

P(Z≤1700)=P(1/700Z≤1.67)=

P(χ24≤1.67)=0.3614

The resultant probability is 0.3614

8 0
3 years ago
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