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3 years ago

What is the solution to the system of equations below? y=-1/3x 6 and x = –6 (–6, 8) (–6, 4) (8, –6) (4, –6)?

Mathematics

1 answer:

Brrunno [24]3 years ago

3 0

Y = -1/3x + 6 . . . (1)
x = -6 . . . (2)
Putting (2) into (1), gives
y = -1/3(-6) + 6 = 2 + 6 = 8

Solution is (-6, 8)

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In ΔVWX, the measure of ∠X=90°, VX = 35, XW = 12, and WV = 37. What is the value of the cosine of ∠W to the nearest hundredth?

devlian [24]

<u>Given</u>:

Given that VWX is a right triangle.

The measure of ∠X is 90°

The length of VX = 35, XW = 12, and WV = 37.

We need to determine the value of cosine of ∠W.

<u>Value of cosine of ∠W:</u>

The value of cosine of ∠W can be determined using the trigonometric ratio.

Thus, we have;

$cos \ W=\frac{adj}{hyp}$

Substituting $\theta=W$ , the side adjacent to W is XW and hypotenuse is WV

Thus, we get;

$cos \ W=\frac{XW}{VW}$

Substituting XW = 12 and WV = 37, we have;

$cos \ W=\frac{12}{37}$

$cos \ W=0.324$

$W=cos ^{-1}(0.324)$

$W=71.09^{\circ}$

Thus, the value of cosine of ∠W is 71.09°

8 0

3 years ago

Read 2 more answers

Negative twenty five minus six

svetoff [14.1K]

-25-6=-31

Change the subtraction sign into positive and add 25 and 6, then put the negative sign after.

8 0

3 years ago

The height of a triangle is 3cm less than twice the base. The area is 10cm2

Kamila [148]

Answer:

The base is 4cm and the height is 5cm.

Step-by-step explanation:

This is a solve the system question. Call H the height of the triangle and B the base. The question tells us:

$H=2B-3$

and

$\frac{B \times H}{2}=10$

Sub the first equation into the second (as H is already isolated). You will end up with a quadratic equation - solve that any way you wish (e.g. quadratic formula). I've provided the factored form below which shows you the roots:

$\frac{B(2B-3)}{2}=10\\\frac{2B^2-3B}{2}=10\\2B^2-3B=20\\2B^2-3B-20=0\\(2B+5)(B-4)=0\\B= - \frac{5}{2},4$

In this question, we take B=4. You can't have a negative side length so the other answer is eliminated. Now sub the value for B into either of the original equations. I'll use the first, again because H is already isolated:

$H=2(4)-3\\H=8-3\\H=5$