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3 years ago

Value of m{8+[b(m-1)+3]} when m = -2 and b = 2/3

Mathematics

1 answer:

Mrrafil [7]3 years ago

3 0

Answer:

-18

Step-by-step explanation:

m = -2 Start with the expression that is within the most number of brackets.

m - 1 = -2 - 1 = -3

Multiply that result by 2/3

-3 * 2/3 = - 2

To that result add 3 which will get you through the square brackets.

- 2 + 3

+ 1

Just outside the square bracket is 8 Eight should be added to 1

8 + 1 = 9

Now you multiply that result by - 2

-2 * 9

= - 18

The answer is 6

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$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\m_{1}=\frac{-10-5}{-7-4}\\\\=\frac{-15}{-11}\\\\m_{1}=\frac{15}{11}\\\\m_{2}=\frac{-9+10}{-4+7}\\\\m_{2}=\frac{1}{3}\\\\m_{3}=\frac{6+9}{7+4}\\\\m_{3}=\frac{15}{11}\\\\m_{4}=\frac{6-5}{7-4}\\\\m_{4}=\frac{1}{3}$

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Option A

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