Answer:
1)-
How to solve your question
Your question is
4(4−72)−9(5+2)
4(4y-7y^{2})-9(5y+2)4(4y−7y2)−9(5y+2)
Simplify
1
Rearrange terms
4(4−72)−9(5+2)
4({\color{#c92786}{4y-7y^{2}}})-9(5y+2)4(4y−7y2)−9(5y+2)
4(−72+4)−9(5+2)
4({\color{#c92786}{-7y^{2}+4y}})-9(5y+2)4(−7y2+4y)−9(5y+2)
2
Distribute
4(−72+4)−9(5+2)
{\color{#c92786}{4(-7y^{2}+4y)}}-9(5y+2)4(−7y2+4y)−9(5y+2)
−282+16−9(5+2)
{\color{#c92786}{-28y^{2}+16y}}-9(5y+2)−28y2+16y−9(5y+2)
3
Distribute
−282+16−9(5+2)
-28y^{2}+16y{\color{#c92786}{-9(5y+2)}}−28y2+16y−9(5y+2)
−282+16−45−18
-28y^{2}+16y{\color{#c92786}{-45y-18}}−28y2+16y−45y−18
4
Combine like terms
2)
−17y+17z+24
See steps
Step by Step Solution:

STEP1:Equation at the end of step 1
((24 - 4 • (5y - 6z)) + 3y) - 7z
STEP2:
Final result :
-17y + 17z + 24
−282+16−45−18
-28y^{2}+{\color{#c92786}{16y}}{\color{#c92786}{-45y}}-18−28y2+16y−45y−18
−282−29−18
-28y^{2}{\color{#c92786}{-29y}}-18−28y2−29y−18
Solution
−282−29−18
Answer:
x = 3 or x = 1
Step-by-step explanation:
Solve for x over the real numbers:
x^2 - 4 x + 3 = 0
Subtract 3 from both sides:
x^2 - 4 x = -3
Add 4 to both sides:
x^2 - 4 x + 4 = 1
Write the left hand side as a square:
(x - 2)^2 = 1
Take the square root of both sides:
x - 2 = 1 or x - 2 = -1
Add 2 to both sides:
x = 3 or x - 2 = -1
Add 2 to both sides:
Answer: x = 3 or x = 1
Answer:
166
Step-by-step explanation:
5/2=2.5
415/2.5
=166
Answer:
17
Step-by-step explanation:
Note that it is given that:
The variable, <em>a</em>, is given the value of 11. Therefore, plug in 11 for <em>a</em> in the given expression. Simplify:
6 + a
a = 11
6 + (11) = 17
17 is your answer.
~
Answer:
Step-by-step explanation:
Given that the probability that an American company will open a location in Shanghai, China is 0.7.
The probability that it will open a location in Beijing, China is 0.4.
The probability that it will open a location in either Shanghai or Beijing or both is 0.8.
the probability that the company will open a location in:
(a) both Shanghai and Beijing :
P(both) = 0.3
(using addition theory of probability for union of sets)
(b) neither Shanghai nor Beijing
= 1- P(AUB)
(c) Beijing but not in Shanghai?
P(Beiging)_P(both) = 
(d) Shanghai given that it opens a location in Beijing
=P(Both)/P(Beijing) = 
