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2 years ago

30 POINTS NO TRICKS JUST 30 POINTS FOR YOU!!!!!!

2 answers:

5 0

First you wold have to put the numbers in order
The ordered data would be 203, 207, 210, 212, 212, 218, 226, 233, 247, 262, 269, 271, 288
You need to find your minimum and maximum points (smallest and largest numbers), first quartile, median (middle number), and third quartile.
Go ahead and make a number line ranging from 203 to 288
Plot your minimum and maximum numbers since you know them already 203=minimum, 288=maximum
Find your median and then plot it (you can do this by looking at your middle number)
Median=262
Put this dot on the number 262 on your number line
To find your first quartile, cut the data in half from your median, and then look at the middle of the data set to the left
First Quartile=212
Go ahead and plot that on the number line as well
You can do the same thing for your third quartile, but instead of looking to the left data set, you have to look at the right data set and find the middle number there
Third Quartile=269
Plot this on your number line
Finally, to make the "box" part of the plot, you have to connect your first quartile, median, and third quartile with a box
Then connect the minimum number to the first quartile with a straight line
Do the same thing with the maximum number and the third quartile
This will give you your "whiskers"

Hope this helped!

algol [13]2 years ago

3 0

Quartile 1 is 211. quartile 2 is 226 , and quartile 3 is 265.5

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"eight times the difference of a number and three is sixty-four"?

morpeh [17]

Answer:

the number would be 11

Step-by-step explanation:

8 · x - 3 = 64

________ _ (divide both sides by 8)

8 8

x - 3 = 8

+ 3 + 3

x = 11

(check:

11 - 3 = 8

8 x 8 = 64 )

5 0

1 year ago

Read 2 more answers

Which table can be created using the equation below? –2 + 4x = y A 2-column table with 3 rows. Column 1 is labeled x with entrie

Pachacha [2.7K]

The correct answer is C. A 2-column table with 3 rows. Column 1 is labeled x with entries negative 5, 0, 3. Column 2 is labeled y with entries negative 18, negative 2, 10.

Explanation:

The purpose of an equation is to show the equivalence between two mathematical expressions. This implies in the equation "–2 + 4x = y" the value of y should always be the same that -2 + 4x. Additionally, if a table is created with different values of x and y the equivalence should always be true. This occurs only in the third option.

x y

5 -18

0 -2

3 10

First row:

-2 + 4 (5) = y (5 is the value of x which is first multyply by 4)

-2 + 20 = -18 (value of y in the table)

Second row:

-2 + 4 (0) y

-2 + 0 = -2

Third row:

-2 + 4 (3) = y

-2 + 12 = 10

5 0

3 years ago

Read 2 more answers

What is the variance of a portfolio invested 21 percent each in a and b and 58 percent in c?

victus00 [196]

Given the following information:

$\begin{tabular}
{|p{1.5cm}|p{1.5cm}|p{1.2cm}|p{1.2cm}|p{1.2cm}|}
\multicolumn{1}{|p{1.5cm}|}{State of economy}\multicolumn{1}{|p{2.6cm}|}{Probability of State of economy}\multicolumn{3}{|p{4.8cm}|}{Rate of Return if State Occurs}\\[1ex] 
\multicolumn{1}{|p{1.5cm}|}{}\multicolumn{1}{|p{2.6cm}|}{}\multicolumn{1}{|c|}{Stock A}&StockB&Stock C\\[2ex]
\multicolumn{1}{|p{1.5cm}|}{Boom}\multicolumn{1}{|p{2.6cm}|}{0.66}\multicolumn{1}{|p{1.27cm}|}{0.09}&0.03&0.34\\
\end{tabular}$
$\begin{tabular}
{|p{1.5cm}|p{1.5cm}|p{1.2cm}|p{1.2cm}|p{1.2cm}|}
\multicolumn{1}{|p{1.5cm}|}{Bust}\multicolumn{1}{|p{2.6cm}|}{0.34}\multicolumn{1}{|p{1.27cm}|}{0.23}&0.29&-0.14\\
\end{tabular}$

Part A:

The expected return on an equally weighted portfolio of these three stocks is given by:

$0.66[0.33 (0.09) + 0.33 (0.03) + 0.33(0.34)] \\ +0.34[0.33 (0.23) + 0.33(0.29) +0.33(-0.14)] \\ \\ =0.66(0.0297 + 0.0099 + 0.1122)+0.34(0.0759+0.0957-0.0462) \\ \\ =0.66(0.1518)+0.34(0.1254)=0.1002+0.0426=0.1428=\bold{14.28\%}$

Part B:

Value of a portfolio invested 21 percent each in A and B and 58 percent in C is given by

For boom: 0.21(0.09) + 0.21(0.03) + 0.58(0.34) = 0.0189 + 0.0063 + 0.1972 = 0.2224 or 22.24%.

For bust: = 0.21(0.23) + 0.21(0.29) + 0.58(-0.14) = 0.0483 + 0.0609 - 0.0812 = 0.028 or 2.8%

Expected return = 0.66(0.2224) + 0.34(0.028) = 0.1468 + 0.00952 = 0.1563 or 15.63%

The variance is given by

$0.66(0.2224-0.1563)^2+0.34(0.028-0.1563)^2 \\ \\ =0.66(0.0661)^2+0.34(-0.1283)^2=0.66(0.00437)+0.34(0.01646) \\ \\ =0.00288+0.0056=\bold{0.00848}$

4 0

3 years ago

What is the distance between the y intercept of the function f(x)=3(2)^x and the y intercept of the function g(x) represented by

balandron [24]

8units sorry if is wrong

8 0

3 years ago

Please Tell me what the answer

Helga [31]

OK for number 3is 70because you add the number that they give you and then subtract 36 106 and you get your answer

3 0

2 years ago