The volume of the cross-section perpendicular to the solid is the amount of space in the cross-section
<h3>How to set up the integral?</h3>
The question is incomplete;
So, I will give a general explanation on how to set up a definite integral for volume of a solid
Assume the solid is a cone;
Using the disk method, the integral of the volume is:

Using the washer method, the integral of the volume is:
![V = \int\limits^a_b {\pi [R(x)^2 -r(x)^2 ]} \, dx](https://tex.z-dn.net/?f=V%20%3D%20%5Cint%5Climits%5Ea_b%20%7B%5Cpi%20%5BR%28x%29%5E2%20-r%28x%29%5E2%20%5D%7D%20%5C%2C%20dx)
Read more about volume integrals at:
brainly.com/question/18371476
Exponents come before subtraction. 5^2=25 and 3^0=1, so 25-1=24.
Six packages were bought. Just count by 2's until you reach 12.
Answer:
x - 51
43
x - 99
-104
75 < 69 - x
150 + x ≤ 144
Step-by-step explanation: