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3 years ago

-3 1/5 ÷ 2/15 Please include steps

2 answers:

8 0

Ok

fisrt we determine sign
negative divided by positive=negative
answer is negative
disregard any signs for now
first convert to from mixed to improper
3 and 1/5=3+1/5=15/5+1/5=16/5

(16/5)/(2/15)
remember the fancy 'invert and multiply'
I won't tell you why because it would take too long, but if you want to know why we invert and multiply, just ask in comments

so, invert an multilply
(a/b)/(c/d)=(ad)/(bc)
(16/5)/(2/15)=(16*15)/(5*2)=(240)/(10)=24

the answer is negative so

-24 is answer

cluponka [151]3 years ago

4 0

-3 1/5 ÷ 2/15
Convert the mixed numbers into improper fractions
- 16/5 divided by 2/15
Convert the division sign into multiplication while flipping the fraction 2/15 to 15/2.
- 16/5 * 15/2
Multiply the numerator by the other numerator while multiplying the denominator by the other denominator.
<span>Final Answer: -240/10 or -24 *All of these answers are equvilant to each other.</span>

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Answer:

Step-by-step explanation:

Step 1:

3 - -5 (4)

Step 2:

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Answer:

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3 years ago

(2³)² solve this problem

max2010maxim [7]

Answer:

$(2^3)^2 = 64$

Step-by-step explanation:

Option 1:

Using the following rule:

$(a^n)^m = a^{nm}$

Put in our expression,

a = 2

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$(a^n)^m = a^{nm}$

$(2^3)^2 = 2^{3*2}=2^6=64$

Option 2:

Using the following rule:

$a^n * a^m = a^{n+m}$

Since our expression is the same as multiplying 2³ with itself, we can write it as a multiplication.

$(2^3)^2 = 2^3 * 2^3$

If we compare this with $a^n * a^m$ , we can see that

a = 2

n = 3

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$2^3*2^3 = 2^{3+3} = 2^6 = 64$

Answer: $(2^3)^2 = 64$

7 0

3 years ago

The area of a rectangular pool is given by the trinomial 2y^2-y-3. What are the possible dimensions of the pool? Use factoring.

RSB [31]

Answer:

(2y−3)(y+1) hope this helps!

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2 years ago

Find the area, in square feet, of a triangle whose base is 42⁄3 feet and whose altitude is 84⁄7 feet. A. 135⁄21 B. 20 C. 40 D. 2

CaHeK987 [17]

Answer:

Option B. $20\ ft^{2}$

Step-by-step explanation:

we know that

The area of a triangle is equal to

$A=\frac{1}{2}bh$

we have

$b=4\frac{2}{3}\ ft$

$h=8\frac{4}{7}\ ft$

Convert mixed numbers to an improper fractions

$b=4\frac{2}{3}\ ft=\frac{4*3+2}{3}=\frac{14}{3}\ ft$

$h=8\frac{4}{7}\ ft=\frac{8*7+4}{7}=\frac{60}{7}\ ft$

substitute the values

$A=\frac{1}{2}(\frac{14}{3})(\frac{60}{7})\\ \\A=\frac{14*60}{2*3*7}\\ \\A=\frac{840}{42} \\ \\A=20\ ft^{2}$

5 0

3 years ago

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Sin(60-theta)sin(60+theta)

ehidna [41]

Step-by-step explanation:

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from difference of two squares:

${ \boxed{(a - b)(a + b) = ( {a}^{2} - {b}^{2} ) }}$

therefore:

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factorise out ¾ :

$= \frac{3}{4} ( { \cos }^{2} \theta - { \sin}^{2} \theta) \\ \\ = { \boxed{ \frac{3}{4} \cos(2 \theta) }}$

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3 years ago

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