Answer:
10⁰×10¹-1¹⁰ < 10⁰×10¹×1¹⁰ < 10⁰+10¹×1¹⁰ < 10⁰+10¹+1¹⁰
Step-by-step explanation:
10⁰×10¹-1¹⁰ = 9
10⁰×10¹×1¹⁰ = 10
10⁰+10¹×1¹⁰ = 11
10⁰+10¹+1¹⁰ = 12
The large hose fills 1 pool in 9 hours written as 1/9
The small hose fills 1 pool in 18 hours, written as 1/18
Now you have 1/9 + 1/18 = 1/x ( x is the unknown time for both hoses).
rewrite 1/9 with a common denominator as 1/18:
1/9 = 2/18
Now you have 2/18 + 1/18 = 1/x
Add the left side:
2/18 + 1/18 = 3/18
Now you have 3/18 = 1/x
Cross Multiply:
3x = 18
Divide both sides by 3"
x = 18/3
X = 6
It will take both hoses 6 hours.
Quantitative data is information that can be measured, while qualitative data is descriptive data which can not be measured.
All five measures (the mean, the median, the trimmed mean, the weighted mean and the mode) can be calculated for quantitative data only, because they all use values in order to be calculated.
Answer:
A
Step-by-step explanation:
As each person counts as 0.02 since theres 50 people in each, A has the correct conclusion and probability count of 0.12 (adult) and 0.40 (child)
V=(1/3)hpir^2
lets say this is original, undoubled volume
so o=v=(1/3)hpir^2
so for new volume, or n, that is r to 2r, doubled radius
n=(1/3)hpi(2r)^2
n=(1/3)hpi4r^2
n=4((1/3)hpir^2)
remmember that o=(1/3)hpir^2
n=4(o)
it is 4 times the old one