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iren [92.7K]
3 years ago
5

Hello there!

Mathematics
1 answer:
otez555 [7]3 years ago
7 0

Answer:

24  Domain: s>=2  or s<=-2

25. 3x^2 +14x +10

26. x^2 -2x+5  

Step-by-step explanation:

24.  Domain is the input or s values

square roots must be greater than or equal to zero

s^2-4 >=0

Add 4 to each side

s^2 >=4

Take the square root

s>=2  or s<=-2


25.  f(g(x))  stick g(x) into f(u) every place you see a u

f(u) = 3u^2 +2u-6

g(x) = x+2

f(g(x) = 3(x+2)^2 +2(x+2) -6

Foil the squared term

       = 3(x^2 +4x+4) +2x+4-6

Distribute

       = 3x^2 +12x+12 +2x+4-6

Combine like terms

   =3x^2 +14x +10


26 f(g(x))  stick g(x) into f(u) every place you see a u

f(u) = u^2+4

g(x) = x-1

f(g(x) = (x-1)^2 +4

Foil the squared term

         = (x^2 -2x+1) +4

         = x^2 -2x+5  

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100 pints help would be greatly appreciated
Veronika [31]

Answer:

  (4, -2)  (see attached)

Step-by-step explanation:

Vector addition on a graph is accomplished by placing the tail of one vector on the nose of the one it is being added to. The negative of a vector is in the direction opposite to the original.

__

<h3>vector components</h3>

The components of the vectors are ...

  u  = (1, -2)

  v = (-6, -6)

Then the components of the vector sum are ...

  2u -1/3v = 2(1, -2) -1/3(-6, -6) = (2 +6/3, -4 +6/3)

  2u -1/3v = (4, -2)

<h3>graphically</h3>

The sum is shown graphically in the attachment. Vector u is added to itself by putting a copy at the end of the original. Then the nose of the second vector is at 2u.

One-third of vector v is subtracted by adding a vector to 2u that is 1/3 the length of v, and in the opposite direction. The nose of this added vector is the resultant: 2u-1/3v.

The resultant is in red in the attachment.

5 0
2 years ago
The number 10^100 is called a googol. What kind of number is a googol? Select all correct answers.
lana66690 [7]

Answer: a, b, c, d

Step-by-step explanation: its not a fraction, its a integer, its positive, and is rational (every integer is rational).

7 0
3 years ago
9 friends are lining up. Joe, Susan, John, and Meredith must be beside each other. How many ways can they line up?
ZanzabumX [31]
<h3>Answer:  17,280</h3>

This is one single number slightly over 17 thousand.

You may need to erase the comma when typing the answer in.

=========================================================

Explanation:

Let's say that another person steps in for Joe, Susan, John, and Meredith. I'll refer to this person as the teacher (perhaps these 9 friends are students on a field trip).

The 9 friends drops to 9-4 = 5 people when those four named people leave the group temporarily. Then it bumps up to 5+1 = 6 people when the teacher steps in. Wherever the teacher is located, the four friends that left will replace the teacher. This guarantees that those four friends stick together.

There are 6! = 6*5*4*3*2*1 = 720 ways to arrange those 6 people. The exclamation mark is a factorial symbol.

Within any of those 720 permutations, we have 4! = 4*3*2*1 = 24 ways to arrange those group of named people when they come back to replace the teacher.

So overall the answer is 4!*6! = 24*720 = 17,280

You may need to erase the comma when typing the answer in.

-------------

Side note: There are 9! = 362,880 ways to arrange all nine friends regardless if those four mentioned people stick together or not. We see that they stick together roughly (17,280)/(362,880) = 0.0476 = 4.76% of the time.

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Answer:

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Step-by-step explanation:

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Answer:

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V = 4π/3 x (32^3)

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V = 137,258.3 ft^3

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